php中的mysqli_num_rows错误。请帮忙 [英] Mysqli_num_rows error in php. Please help
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问题描述
我已经为我的拼贴项目编写了php代码。我使用了php / mysql的mysqli_num_rows（）函数，我得到了这个错误： mysqli_num_rows（）期望参数1是mysqli_result boolean在中给出
这是我的全部代码：
i have write the php code for my collage project. i used mysqli_num_rows() function of php/mysql and i get this error:mysqli_num_rows() expects parameter 1 to be mysqli_result boolean given in
here is my whole code:
<pre><?php require_once('inc/top.php');?>
</head>
<body>
<!--navbae-->
<?php require_once('inc/nav.php');?>
<!--End navbar-->
<div class="container-fluid">
<div class="row">
<?php require_once('inc/sidebar.php');?><!--end sidebar-->
<div class="col-md-9">
<h1> Add Users <small>Add New Users Profile</small></h1><hr>
<ol class="breadcrumb">
<li><a href="index.php"> Dashbord</a></li>
<li class="active"> Add Users</li>
</ol>
<?php
if(isset($_POST['submit'])){
$name = mysqli_real_escape_string($cn, $_POST['name']);
$username = mysqli_real_escape_string($cn, $_POST['user-name']);
$username_trim = preg_replace('/\s+/','',$username);
$email = mysqli_real_escape_string($cn,$_POST['email']);
$password = mysqli_real_escape_string($cn,$_POST['password']);
$role = $_POST['role'];
$image = $_FILES['image']['name'];
$image_tmp = $_FILES['image']['tmp_name'];
// $check_query = "SELECT * FROM user WHERE user_name = '$username' or email = '$email'";
$check_run = mysqli_query($cn,"SELECT * FROM `user` WHERE `user_name` = '$username' or `email` = '$email'");
if(empty($name) or empty($username) or empty($email) or empty($password) or empty($image)){
$error = "ALL (*) FEILDS ARE REQUIRED";
}
else if($username != $username_trim)
{
$error = "Don't use spaces in Username";
}
else if(mysqli_num_rows($check_run)>0)
{
$error = "Username or email allready Exists";
}
else
{
$msg = "Success";
}
}
?>
<div class="row">
<div class="col-md-8">
<form action="" method="post" enctype="multipart/form-data">
<div class="form-group">
<label for="name">Name:*</label>
<?php
if(isset($error)){
echo "<span class='pull-right' style='color:red;'>$error</span>";
}
?>
<input type="text" name="name" id="name" class="form-control" placeholder="Name">
</div>
<div class="form-group">
<label for="user_name">User Name:*</label>
<input type="text" name="user-name" id="user-name" class="form-control" placeholder="User Name">
</div>
<div class="form-group">
<label for="email">E-mail:*</label>
<input type="text" name="email" id="email" class="form-control" placeholder="E-mail">
</div>
<div class="form-group">
<label for="password">Password:*</label>
<input type="password" name="password" id="password" class="form-control" placeholder="Password">
</div>
<div class="form-group">
<label for="role">Role:*</label>
<select name="role" id="role" class="form-control">
<option value="author">Author</option>
<option value="admin">Admin</option>
</select>
</div>
<div class="form-group">
<label for="profile">Profile Picture:*</label>
<input type="file" name="image" id="image">
</div>
<input type="submit" value="Add user" name="submit" class="btn btn-primary">
</form>
</div>
<div class="col-md-4"></div>
</div>
</div>
</div>
</div>
<?php require_once('inc/footer.php');?>
ih我将获得最佳解决方案。
提前感谢。
我尝试过的方法：
我会尝试一些替代但它不起作用。
i hope i'll get the best solution.
thanks in advance.
What I have tried:
i'd try some alternation but it dosen't work.
推荐答案
_POST [' submit']））{
_POST['submit'])){
name = mysqli_real_escape_string（
name = mysqli_real_escape_string(
cn，
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