错误：'std :: cout.std :: basic_ostream中'operator ='不匹配 [英] Error: no match for 'operator=' in 'std::cout.std::basic_ostream

问题描述

给出以下代码：

int number = 49;



执行以下语句后输出结果是什么？

Given the following code:
int number = 49;

what will the output be after the following statements are executed?

if(number >= 50)
cout << "yes" << endl;
cout << number = number + 1;

[已添加]

输出什么？ 50或是50？

[/ added]



我的尝试：

[added]
What will be the output? 50 or Yes 50?
[/added]

What I have tried:

#include <iostream>
using namespace std;

int main ()

{
    int number = 49;

    if ( number >= 50)
    {
        cout << "Yes " << endl;
        cout << number = number + 1;
    }

}

推荐答案

引用：

cout<< number = number + 1;

cout << number = number + 1;

这个语句错误（正如编译器注意到:-)），因为插入操作符的优先级高于赋值操作符。







以下程序

This statement is wrong (as the compiler noticed :-) ), because the insertion operator has higher precedence than the assignment one.



The following program

#include <iostream>
using namespace std;

int main()
{
  int number = 49;

  if ( number >= 50)
    cout << "Yes " << endl;
  cout << (number = number + 1);
}

仅输出 50 。

此代码的输出：

The output od this code:

#include <iostream>
using namespace std;
int main ()
{
    int number = 49;
    if ( number >= 50)
    {
        cout << "Yes " << endl;
        cout << (number = number + 1);
    }
}

不算什么，因为我理解这段代码。

is nothing as I understand this code.

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