保持选择列表的值 [英] Keep value of select list

问题描述

我有一个基于查询的选择列表。它将结果发布到同一页面。



但是，即使更新页面后，列表中的选项也会返回到列表的顶部，而不是我已选择。



在选择框中保留该选项的最简单方法是什么？



我我们在网上看到过例子，但它们都是指输入的选项，而不是查询列表，我无法弄清楚如何使代码适应查询列表。



我已经在下面列出了相关代码。



我尝试了什么：

I have a Select list based on a query. It posts the results to the same page.

However, even after updating the page, the choice in the list returns to the top of the list, rather than what I had selected.

What is the simplest way to retain that choice in the select box?

I have seen examples online, but they all refer to typed-in options, not a query list, and I can't figure out how to adapt the code to a query list.

I have included the relevant code below.

What I have tried:

<form action="http://www.pabirds.org/joomla/index.php/birding/birds-of-pa" method="post" name="form1" target="_self" id="form1">
<label for="Species" class="MediumSerifText">Select Species (Alphabetical order):</label>
<select name="Species" id="Species" onchange="this.form.submit()">
<?php
do {  
?>
        <option value="<?php echo $row_rsSelectSpeciesAlpha['ID']?>"><?php echo $row_rsSelectSpeciesAlpha['CommonName']?></option>
        <?php
} while ($row_rsSelectSpeciesAlpha = mysql_fetch_assoc($rsSelectSpeciesAlpha));
  $rows = mysql_num_rows($rsSelectSpeciesAlpha);
  if($rows > 0) {
      mysql_data_seek($rsSelectSpeciesAlpha, 0);
	  $row_rsSelectSpeciesAlpha = mysql_fetch_assoc($rsSelectSpeciesAlpha);
  }
?>
</select>

</form>

推荐答案

row_rsSelectSpeciesAlpha ['ID']？>>< ;？php echo

row_rsSelectSpeciesAlpha['ID']?>"><?php echo

row_rsSelectSpeciesAlpha ['CommonName']？>< / option>
<？php
} while（

row_rsSelectSpeciesAlpha['CommonName']?></option> <?php } while (

row_rsSelectSpeciesAlpha = mysql_fetch_assoc（

row_rsSelectSpeciesAlpha = mysql_fetch_assoc(

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