如果所有3都是相同的打印，则输入3个整数值，否则打印0 [英] Input 3 integer values if all 3 are same print 1 else print 0

问题描述

#include<stdio.h>
int main()
{
  int a,b,c;
  scanf("%d\n%d\n%d\n",&a,&b,&c);
  if(a != b || a != c)
  {
    printf("1");
  }
  else if(b != c)
  {
    printf("1");
  }
  else
  {
    Printf("0");
  }
  return 0;
}

我的尝试：



输入3个整数，如果3个是相同的打印1，则打印0

What I have tried:

to input 3 integers if 3 are same print 1 else print 0

推荐答案

在等待代码中的问题描述时，给出一个尝试调试。



有一个工具可以让你看到你的代码在做什么，它的名字是调试器。它也是一个很好的学习工具，因为它向你展示了现实，你可以看到哪种期望与现实相符。

当你不明白你的代码在做什么或为什么它做它做的时候，答案就是答案是调试器。

使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量。



调试器 - 维基百科，免费的百科全书 [ ^ ]



掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]

使用Visual Studio 2010进行基本调试 - YouTube [ ^ ]

调试器在这里向您展示您的代码正在做什么，您的任务是与什么进行比较应该这样做。

调试器中没有魔法，它没有找到错误，它只是帮助你。当代码没有达到预期效果时，你就接近了一个bug。

While waiting for a description of the problem in your code, give a try to debugger.

There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]

Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

目前，你的代码是这样做的：

Currently, your code does this:

1. 如果a不是b或a不是c，则打印 1 。
2. 如果b不是c，则打印 1 。
3. 如果上述条件不成立，请打印 0 。

这听起来不像你想要的;如果所有值都相同，你想打印 1 ，所以你想要这个：

This does not sound like what you want; you wanted to print 1 if all values are the same, so you want this:

if (a == b && a == c) // if a is b AND a is c (then b is c, so a and b and c are the same)
{
    printf("1");
}
else // the above conditions is not true; at least one of the three numbers is different
{
    printf("0");
}

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