初学者的一点指导 [英] A little guidance for a beginner

问题描述

我不明白问题出在我的代码中，我没有看到这样的错误所以我不知道从哪里开始调试它。我现在只学习用C ++编写代码大约一个月了。所以，问题是从const std :: string到char没有合适的转换函数。在这行代码中horses [i] .name = HorseNames [i];在HorseNames下。



:我添加声明

I do not understand the issue is in my code, I have not seen an error like this so I don't know where to start to debug it. I have only been learning to write code in C++ for about a month now. So, the issue is this "No suitable conversion function from const std::string to char exist." in this line of code "horses[i].name = HorseNames[i];" under HorseNames.

edit:: I add the declaration

struct Horse
{
	char name;
	int distance;
	int eventOffSet;
	int ID;
};

        array <Horse, horseCount> horses;
	const string HorseNames[] = { "Black Beauty", "Sea Biscuit", "Bucephalus", 
                                      "Man o War", "Marengo", "Winning Colors" };

	horses[0].ID = 1;
	horses[1].ID = 2;
	horses[2].ID = 3;
	horses[3].ID = 4;
	horses[4].ID = 5;
	horses[5].ID = 6;


 for (int i = 0; i < horseCount; i++)
		{
			horses[i].name = HorseNames[i];
			cout << "These are the Galent Steeds racing today!: "  
                             <<  horses[i].name << endl;
		}

我的尝试：



我用google搜索它并找不到任何东西，我试图将我的const字符串更改为静态字符串，将其重命名为char并且似乎没有任何效果。

What I have tried:

I have googled it and couldn't find anything, I tried to change my const string to a static, renamed it to char and nothing seemed to work.

推荐答案

正如已经建议你应该显示tpyes的声明。



但是，从错误信息中可以假设这样的事情：

As already suggested you should show the declaration of the tpyes.

However, from the error message something like this can be assumed:

std::string HorseNames[MAX_HORSES];
struct {
    char name;
    // Probably more members here
} Horses;
Horses horses[MAX_HORSES];

然后 HorseNames [i] 是 std :: string 无法分配给单个 char ，如 horses [i] .name 。



您可能希望 Horses.name 成为 std :: string 也是 char 数组。在后一种情况下，您无法使用赋值，但必须复制字符串：

Then HorseNames[i] is a std::string which can not be assigned to a single char like horses[i].name.

You probably want Horses.name to be a std::string too or a char array. In the latter case you could not use an assignment but have to copy the string:

char name[MAX_NAME_LEN];
// Use strncpy or a safe string copy method here to avoid buffer overruns
strncpy(name, HorseNames[i], sizeof(name) / sizeof(name[0]));
// NULL terminate when using strncpy and string is too long
name[sizeof(name) / sizeof(name[0]) - 1] = '\0';

您不能在中存储字符串 char 变量; char 类型只能包含一个字符。你需要一个指向字符串的指针（ char * ），或者需要一个字符数组（ char [] ）作为Jochen建议如上。

You cannot store a string in a char variable; a char type can hold only a single character. You need either a pointer to a string (char*), or a character array (char[]) as Jochen has suggested above.

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