排序边界框与铊（）：opencv的机器人 [英] Sort bounding boxes with Tl() : Opencv Android

问题描述

我试图包围盒与Y轴进行排序，然后X轴，但结果我从TL找到（）x和TL（）。y的有点混乱，大量的工作后，我找不到任何东西文档。这里有一些结果，请看一看。我想他们是为了从1到30

I am trying to sort the bounding boxes with y axis and then x axis but the results I find from tl().x and tl().y are bit confusing and after lot of work I couldn't find anything in documentation. Here are some results please take a look. I want them to be in order from 1 to 30

code：

m = Utils.loadResource(MainActivity.this, R.drawable.sheet1, Highgui.CV_LOAD_IMAGE_COLOR);
//Mat original = Utils.loadResource(MainActivity.this, R.drawable.sheet1, Highgui.CV_LOAD_IMAGE_COLOR);
Bitmap bm = Bitmap.createBitmap(m.cols(), m.rows(),Bitmap.Config.ARGB_8888);

Imgproc.cvtColor(m, m, Imgproc.COLOR_BGR2GRAY);
Imgproc.medianBlur(m, m,3); 
Imgproc.threshold(m, m, 0, 255, Imgproc.THRESH_OTSU);
Core.bitwise_not(m, m);
Imgproc.dilate(m, m, Imgproc.getStructuringElement(Imgproc.MORPH_RECT, new Size(1,118)));

java.util.List<MatOfPoint> contours = new ArrayList<MatOfPoint>();                  
Imgproc.findContours(m.clone(), contours, new Mat() ,Imgproc.RETR_EXTERNAL , Imgproc.CHAIN_APPROX_SIMPLE);
Rect rect = Imgproc.boundingRect(contours.get(35));                         
Toast.makeText(MainActivity.this, "TL:"+rect.tl()+"BR:"+rect.br(), Toast.LENGTH_LONG).show();

编辑：

这是剪切区域和上面显示的坐标是这些框。

This is cropped region and the coordinates showing above are of these boxes.

原始图片：

推荐答案

所以，你要优先排序先从左到右，然后从上到下。 x坐标是更重要的，但是，对于的相似 X怎样才算是y。写一个排序功能，在其中您有伪code看起来像这样的关系：

So you want to sort with priority first left to right and then top to bottom. x coordinate is more important, however for similar x what counts is the y. Write a sorting function, in which you have a relationship which in pseudocode looks like this:

boolean isLessThan(bboxA,bboxB,unsigned int tolerance = 100) {

    if (bboxA.tl().x + tolerance < bboxB.tl().x);
         return true;
    if (bboxB.tl().x + tolerance < bboxA.tl().x);
         return false;
    return (bboxA.tl().y < bboxB.tl().y);

    }

（或硬code 宽容）

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