如何检查model.count为null或大于2然后输入codition [英] How to check model.count is null or greater then 2 then enter in codition

问题描述

if（Model.Count（）< 2）

{



}





亲爱的先生



我想知道如何检查模型。 count = null然后不抛出异常，它进入Codtion内部



我尝试过：



先生，当它获得空值时，条件应该是真的，当model.value = 1然后条件为真，但是当模型时。值= 2然后条件错误





所以请帮助我

if (Model.Count() < 2)
{

}


Dear sir

I Want to Know How to Check if Model. count = null then do not throw exception and it goes in inside of Codtion

What I have tried:

sir when it get null value then condition should true when model.value=1 then condition true but when model. value =2 then condition false


so please help me

推荐答案

试试这个：

Try with this:

if (Model!=null) && (Model.Count<2)) <br />
{<br />
}

解释：只有当模型不为null（fisrt条件）时，如果model.count小于2，则chek

Explanation: only when the model is not null (fisrt condition) chek if the model.count is less than 2

我认为问题是Model是null，而你没有期待。

I think that the problem is that Model is null, and you do not expect that.

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