如何打印此代码? [英] How do I print this code?

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问题描述

请以c编程语言打印此形状。





*

**

***

****

***

**

*



我尝试过:



#include< stdio .h>

int main(无效)

{

int row,col;



for(row = 0; row< 4; row ++)

{

for(col = 0; col< row; col ++)

{

printf();

}

printf(\ n);

please print this shape as in c programming language.


*
**
***
****
***
**
*

What I have tried:

#include <stdio.h>
int main (void)
{
int row, col;

for (row=0; row < 4; row ++)
{
for (col=0; col<row;col++)
{
printf(" ");
}
printf("\n");

推荐答案

引用:

请按照c编程语言打印此形状。

please print this shape as in c programming language.



不,这是你的作业。

试错法是一个很好的学习方法,但为此,你必须尝试。

如果可能,请打破部分问题。

首先,尝试做


No, this is YOUR homework.
Trial and error is a good method to learn, but for this, YOU have to do tries.
When it is possible, break the problem in parts.
First, try to do

*
**
***
****


然后


then

***
**
*





我们不做你的HomeWork。

HomeWork不会测试你乞求别人做你的工作的技巧,它会让你思考和帮助你老师检查您对所学课程的理解以及您应用这些课程时遇到的问题。

你的任何失败都会帮助你的老师发现你的弱点并设定补救措施。

你的任何失败都会帮助你了解什么有效,什么无效,被称为'试错'学习。

所以,试一试,重读课程并开始工作。如果您遇到特定问题,请显示您的代码并解释这个问题,我们可能会提供帮助。



作为程序员,您的工作是创建算法解决特定问题,你不能依赖别人永远为你做,所以有一段时间你必须学会​​如何。而且越快越好。

当你要求解决方案时,就像试图通过培训其他人来学习开车一样。

创建算法基本上是找到数学并做出必要的调整以适应你的实际问题。



发展的概念就像这个词所暗示的那样:系统地使用科学和满足特定目标或要求的技术知识。 BusinessDictionary.com [ ^ ]

这与有一个不一样快速谷歌并放弃,如果我找不到正确的代码。



We do not do your HomeWork.
HomeWork is not set to test your skills at begging other people to do your work, it is set to make you think and to help your teacher to check your understanding of the courses you have taken and also the problems you have at applying them.
Any failure of you will help your teacher spot your weaknesses and set remedial actions.
Any failure of you will help you to learn what works and what don't, it is called 'trial and error' learning.
So, give it a try, reread your lessons and start working. If you are stuck on a specific problem, show your code and explain this exact problem, we might help.

As programmer, your job is to create algorithms that solve specific problems and you can't rely on someone else to eternally do it for you, so there is a time where you will have to learn how to. And the sooner, the better.
When you just ask for the solution, it is like trying to learn to drive a car by having someone else training.
Creating an algorithm is basically finding the maths and make necessary adaptation to fit your actual problem.

The idea of "development" is as the word suggests: "The systematic use of scientific and technical knowledge to meet specific objectives or requirements." BusinessDictionary.com[^]
That's not the same thing as "have a quick google and give up if I can't find exactly the right code".


我们不做你的功课:这是有原因的。它就是为了让你思考你被告知的事情,并试着理解它。它也在那里,以便您的导师可以识别您身体虚弱的区域,并将更多的注意力集中在补救措施上。

亲自尝试,您可能会发现它并不像您想象的那么难! />


如果您遇到特定问题,请询问相关问题,我们会尽力提供帮助。但是我们不会为你做这一切!



但我会给你一些线索:你需要两个循环,一个接一个。第一个循环打印长度增加的行,第二个循环打印长度减少的行。每个人都需要在其中打第二个循环来打印每一行。

首先让第一个循环工作,然后你几乎有第二个循环的代码。

使第一个循环的行数从1到4(包括1和4),这将告诉你每行要打印多少个星。

同样,使第二个循环从3到1运行。



这并不复杂 - 所有你需要做的就是坐下来思考几分钟然后你会在那里!
We do not do your homework: it is set for a reason. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.
Try it yourself, you may find it is not as difficult as you think!

If you meet a specific problem, then please ask about that and we will do our best to help. But we aren't going to do it all for you!

But I'll give you a couple of clues: you need two loops, one after the other. The first loop prints the rows that are increasing in length, the second prints the rows that are decreasing in length. Each of them needs a second loop inside it to print each line.
Start by getting the first loop working, and then you pretty much have the code for the second one.
Make the row count of your first loop run from 1 to 4 inclusive, and that will tell you how many stars to print on each row.
Similarly, make the second loop run from 3 to 1 inclusive.

This isn't complicated - all you have to do is sit down and think for a couple of minutes and you'll be there!


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