Begineer关于伯爵的问题 [英] Begineer's question about count

问题描述

参考书显示答案是

The reference book shows the answer is

h(g) = 3.1415e-005
count = 18

但我的答案是

but my answer is

h(g) = 3.1415e-005count = 0

#include <stdio.h>
int main()
{
	int count, a = 2046;
	short b = 234;
	long c = 5555;
	unsigned int d = 1234;
	char e = 'z';
	float f = 3.14159f;
	double g = 3.1415926535898;
	double h = 3.1415e-5;
	
	printf("a(d) = %d\n", a);
	printf("a(o) = %o\n", a);
	printf("a(x) = %x\n", a);
	printf("b(d) = %d c(d) = %d\n", b, c);
	printf("d(u) = %u\n", d);
	
	printf("e(c) = %c\n", e);
	
	printf("f(f) = %f\n", f);
	printf("g(f) = %f\n", g);
	printf("g(e) = %e\n", g);
	printf("g(g) = %g\n", g);
	printf("h(f) = %f\n", h);
	printf("h(e) = %e\n", h);
	printf("12345678901234567890\n");
	printf("h(g) = %g%n\n", h, &count);
	printf("count = %d\n", count);
	printf("b(d) = %d f(f) = %f\n", b, f);
	
	return 0;
}

我的尝试：



删除％n和&在

What I have tried:

remove %n and & in

printf("h(g) = %g%n\n", h, &count);

推荐答案

你没有指定一个值来计算，所以它仍然是偶然初始化的零值。

Nowhere do you assign a value to count, so it remains at the fortuitously initialised vaue of zero.

程序

The program

#include <stdio.h>
int main()
{
  double h = 3.1415e-5;
  int count;

  printf("h(g) = %g%n\n", h, &count);
  printf("count = %d\n", count);
  return 0;
}

产出

Outputs

h(g) = 3.1415e-05
count = 17

在我的 Linux 框中（ gcc 5.4.0 ）。

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