如何使用C＃在XML中查找重复节点 [英] How to find the duplicate nodes in XML using C#

问题描述

我有非结构化XML，如下所示

I have unstructured XML as shown below

<Root name="FIRST" serviceidentifier="">
  <SERVER response="SERVICE NOT FOUND" type="SERVER" identifier="NONE" misc="NOT FOUND"/>
</Root>
<Root name="SECOND" serviceidentifier="">
  <SERVER response="SERVICE NOT FOUND" type="SERVER" identifier="NONE" misc="NOT FOUND"/>
</Root>	
<Root name="FIRST" serviceidentifier="">
  <SERVER response="SERVICE NOT FOUND" type="SERVER" identifier="NONE" misc="NOT FOUND"/>
</Root>

我必须找到具有重复节点的XML的行号，其属性为首先喜欢根名称= FIRST



我尝试过：



我是XML新手所以请给我一个完整的代码



感谢您的帮助.....

I Have to find the line number of the XML which has duplicate nodes with the attribute "FIRST" like "Root name=FIRST"

What I have tried:

I am New to XML So please give me a Complet CODE

Thanks for your help .....

推荐答案

您的第一个也是最严重的问题是这不是XML（无效），因此您无法将其加载到 XmlDocument [ ^ ] object ...

首先将其包装到虚拟根目录中使其成为有效的XML，而不是使用XMLDocument和XPath来查找具有相同属性的元素......

XPath示例 [ ^ ]

[ ^ ]

< a href =https://docs.microsoft.com/en-us/dotnet/standard/data/xml/select-nodes-using-xpath-navigation>使用XPath导航选择节点Microsoft Docs [ ^ ]

Your first and most severe problem is that this is not an XML (not valid), so you can not load it into an XmlDocument[^] object...
So first wrap it into a virtual root make it valid XML, than use XMLDocument and XPath to find elements with the same attributes...
XPath Examples[^]
[^]
Select Nodes Using XPath Navigation | Microsoft Docs[^]

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