Chrome“脚本可能只会关闭由它打开的窗口”错误 [英] Chrome “Scripts may close only the windows that were opened by it” error

问题描述

window.close();//false

window.open(location, '_self', '');
window.close();//false

open(location, '_self').close();//false

Chrome 45.0.2454.85 m，Firefox也有问题。

Chrome 45.0.2454.85 m, Firefox also has the problem.

请帮忙...

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推荐答案

您应该将打开的窗口存储在变量中。

You should store your opened window in a variable.

var popup = window.open(location, '_blank', '');
popup.close();

编辑：因为你在同一个屏幕上打开一个新页面，在_self中打开不起作用想像我编辑的那样做_blank。

Opening in _self does not work since you open a new page in the same screen, you might want to do _blank like i've edited.

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