如果对象包含在另一个数组中，则从数组中删除它 [英] Remove object from array if it is contained in another array

问题描述

我试图从数组中删除一个对象，如果该对象的属性（唯一）包含在另一个数组中。我知道我可以这样做一个嵌套的for循环：

I am trying to remove an object from an array, if that object's property (unique) is included in the other array. I know I can do a nested for-loop like this:

for(i = 0; i < array.length; i++) {
    for(j = 0; j < array2.length; j++) {
        if(array[i].Email === array2[j].Email) {
            //remove array[i] object from the array
        }
    }
}

或者其他什么。这样的事情。那有ES6过滤器吗？我可以轻松地对带有字符串的常规数组进行过滤，但是使用对象数组进行过滤会有点棘手。

Or whatever. Something like that. Is there an ES6 filter for that? I can easily do a filter up against a regular array with strings, but doing it with an array of objects is a bit more tricky.

推荐答案

不是最优，但试试这个

array = array.filter( function( item ){
  return array2.filter( function( item2 ){
    return item.Email == item2.Email;
  }).length == 0;
});

尝试查找，它赢了迭代所有元素并在第一次匹配后中断

Try with find as well, it won't iterate all the elements and will break after first match itself

array = array.filter( function( item ){
  return array2.find( function( item2 ){
    return item.Email == item2.Email;
  }) == undefined;
});

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