用于验证地址的JavaScript正则表达式 [英] JavaScript regex to validate an address

问题描述

我想使用正则表达式验证JavaScript中的居住地址，但我对正则表达式了解不多，我尝试过建立自己的正则表达式（ / ^ [a-zA-Z] \\\]（\d）？$ / ）但它似乎无法正常工作。

I would like to validate residence address in the JavaScript using regex, but I dont know much about the regex, what I have tried is to build my own regex (/^[a-zA-Z\s](\d)?$/) but it doesn't seem to work properly.

我想达到的目标是允许字母，空格和至少一个数字（这是必需的），也应该有可能插入斜杠 / ，但它不应该是必需的。

What I want to achieve is to allow letters, spaces and at least one digit (thats required) and also there should be a possibility to insert the slash / but it shouldnt be required.

任何人都可以帮我吗？

推荐答案

我会帮你的但是当你习惯了正则表达式时，你会发现自己变得更加具体。首先，让我们检查你的正则表达式：

I'll get you started, but you'll find yourself becoming more specific as you get accustomed to regular expressions. First, let's examine your regex:

/^[a-zA-Z\s](\d)?$/

这里需要注意的是，这个正则表达式最多只能匹配两个 - 字符串！字符类 [...] 匹配单个字符：在您的情况下，字母和空格。你需要将它与所谓的量词结合起来，例如 * 意思是零或更多， + 表示一个或多个，？表示零或一个。你在其他地方使用过量词，（\d）？，你说的是零或一数字字符。但你真正想要的看起来更像是这样：

The essential thing to note here is that this regex will only match, at most, a two-character string! The character class, [ ... ], matches a single character: in your case, letters and whitespace. You need to combine this with what's called a quantifier, e.g. * meaning "zero or more", + meaning "one or more", and ? meaning "zero or one". You've used a quantifier elsewhere, (\d)?, where you're saying "zero or one" digit character. But what you really want looks more like this:

/^[a-zA-Z\s\d\/]+$/

这里，我们说一个或多个字母，空格，数字或斜杠（请注意，正斜杠必须使用反斜杠进行转义）。

Here, we're saying "one or more" letters, whitespace, digits, or slashes (note that the forward slash must be escaped using a backslash).

最后，你说要要求至少一个 数字。这可以通过正则表达式中更高级的构造来实现，称为外观断言。你想要这个：

Finally, you say want to require "at least one" digit. This can be achieved with a more advanced construct in regular expressions, called "lookaround assertions." You want this:

/^(?=.*\d)[a-zA-Z\s\d\/]+$/

特别是正向前瞻断言，你可以自己研究。另一种没有超前断言的方法是：

That, in particular, is a positive lookahead assertion, which you can research yourself. An alternate way of doing this, without lookahead assertions, would be:

/^[a-zA-Z\s\d\/]*\d[a-zA-Z\s\d\/]*$/

这显然更复杂，但是当你能够理解这一点时，你知道你正在理解正则表达式。祝你好运！

This is obviously more complicated, but when you're able to understand this, you know you're well on your way to understanding regular expressions. Good luck!

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