无法在Express 4.0中将路由拆分为单独的文件 [英] Unable to Split Routes into Separate Files in Express 4.0

问题描述

我正在尝试将以 / api 结尾的所有路线重定向到 manager.js 将它路由到 / me 。

I'm trying to redirect all my routes ending with /api to a manager.js which will then route it to /me.

因此，对 / me <的完全限定请求/ code>应该看起来像 / api / me 。在Express 3.x中，将路由分割成单独的文件很容易，但我在4.0中遇到了麻烦。

So, a fully qualified request to /me should look like /api/me. Splitting routes up into separate files was easy in Express 3.x, but I'm having trouble in 4.0.

app.js

app.use('/api',require('./routes/manager'));

manager.js

var express = require('express');
var manager = express.Router();
module.exports = function() {    
    manager.use('/me',require('../routes/me'));
};

me.js

var express = require('express');
var me = express.Router();

module.exports = function() {

    me.route('/')
        .get(function(req,res){
            res.send("Welcome to Me");
    });

};

当我去 localhost：8080 / api / me ，没有任何反应，页面不断加载。

When I go to localhost:8080/api/me, nothing happens, the page keeps loading.

感谢您的帮助！

推荐答案

您没有正确地通过路由器对象。请记住，这就是你要做的事情：

You are not quite properly passing through the Router objects. Keep in mind that this is what you are trying to do:

app.use('/api', express.Router());

但你现在实际做的是：

app.use('/api', function(){
    express.Router()
});

因此，您应该导出路由器<而不是导出函数/ code>本身。

So you instead of exporting a function, you should be exporting the Router itself.

manager.js

var express = require('express');
var manager = express.Router();

manager.use('/me',require('../routes/me'));

module.exports = manager;

me.js

var express = require('express');
var me = express.Router();

me.route('/').get(function(req,res){
    res.send("Welcome to Me");
});

module.exports = me;

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