AJAX - 404与超薄PHP [英] AJAX - 404 with Slim PHP
问题描述
在我的Slim PHP应用程序中尝试使用AJAX获取数据时,我在控制台中获得了404(未找到)。这是错误消息:
I'm getting a 404 (Not found) in the console when trying to get data with AJAX in my Slim PHP application. Here's the error message :
http://localhost:8888/Project/mods/public/edit-mod/ajax/get-categories?gameID=1 404 (Not Found)
这是在routes.php文件中定义的路由(正确包含,所有其他路线都有效):
Here's the route defined in a routes.php file (that is correctly included, all the other routes are working) :
$app->get("/ajax/get-categories/", function() use ($app, $User, $Game, $Mod){
//Fetch data and echo it
});
最后,这是我在JS脚本中调用AJAX页面的方式:
Finally, here's how I'm calling the AJAX page in the JS script :
$.get("ajax/get-categories", {gameID: gameID}, function(data){
//Do something with data
});
我尝试将Slim路线更改为ajax / get-categories /(不含前导 /
)但它没有改变任何东西,我也尝试了一堆不同的AJAX调用路径(在JS脚本中)但没有任何效果,我总是得到404没有无论如何。
I tried changing the Slim route to "ajax/get-categories/" (without the leading /
) but it didn't change anything, and I also try a bunch of different paths for the AJAX call (in the JS script) but nothing worked, I always get the 404 no matter what.
当我在我的脚本中只调用 ajax / get-categories
时,似乎是将当前页面(ex edit-mod /
)附加到路线,这可能是我的问题。
When I'm calling only ajax/get-categories
in my script, it seems to be appending the current page (ex edit-mod/
) to the route, maybe that's my problem.
有没有办法匹配以 ajax / get-categories
结尾的每条路线,以便两者都 upload / ajax / get-categories
和 edit-mod / ajax / get-categories
会有效吗?
Is there a way to match every route that ends with ajax/get-categories
, so that both upload/ajax/get-categories
and edit-mod/ajax/get-categories
will work?
如果您需要更多代码,请告诉我,我想我已经包含了与问题相关的所有内容。
Let me know if you need any more code, I think I've included everything that is relevant to the problem.
推荐答案
我使用过Slim Framework;)
I have worked with Slim Framework ;)
看,这就是我设法让Ajax与Slim框架一起工作的方式。
Look, this is how I have managed to make Ajax work with Slim framework.
首先,你必须声明路径两者 get 和发布(当我第一次尝试声明发布时,它不起作用):
First, you have to declare the routes both get and post (when I first tried declaring post only, it didn't work):
获取:
$app->get('/your/url',$permission(),function() use ($app){
//here you can check whether it is an ajax call
})->name('your.url');
POST:
$app->post('/your/url',$permission(),function() use ($app){
//get the data:
$request = $app->request;/*getting post data*/
$var1 = $request->post('var1');
$var2 = $request->post('var2');
//echo '| For log and testing purposes you can echo out the gotten values. Var1: '.$var1.'. Var2: '.$var2;
//DO YOUR STUFF here, for example, database processing with Eloquent ORM
$saved=$user->save();
if($saved){ echo '[success]';}else{echo '[error]';}/*http://stackoverflow.com/a/27878102/1883256*/
})->name('your.url.post');
现在,从视角来看,像这样制作你的ajax:
Now, from the view side, make your ajax like this:
<script type="text/javascript">
/*Referencias: https://www.codecourse.com/forum/topics/use-jquery-ajax-post-with-the-authentication-series/527*/
/*Permissions*/
$(function() {
$('#your_element').change(function(){
var var1 = this.val1;
var var2 = this.val2;
console.log('Value1 is: '+var1+' and value2 is: '+var2);
$.ajax({
data: {var1: var1,var2: var2,{{ csrf_key }}: "{{ csrf_token }}"},
type: "POST",
dataType: "json",
headers: { "cache-control": "no-cache" },
url: "/your/url" //add ../your/url if needed
});//ajax end
});
});
});
</script>
就是这样。
- 如果您在表单中使用csrf令牌,那么发送它也很重要。
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