如何根据2个属性删除数组中的重复对象？ [英] How to remove duplicates objects in array based on 2 properties?

问题描述

我有一组房间对象，我正在根据他们的 room_rate_type_id 属性从数组中删除重复对象：

I have an array of room objects and I am currently removing duplicates objects from the array based on their room_rate_type_id property:

const rooms = [{
    room_rate_type_id: 202,
    price: 200
  },
  {
    room_rate_type_id: 202,
    price: 200
  },
  {
    room_rate_type_id: 202,
    price: 189
  },
  {
    room_rate_type_id: 190,
    price: 200
  }
];

const newRooms = rooms.filter((room, index, array) => {
  const roomRateTypeIds = rooms.map(room => room.room_rate_type_id);
  // Returns the first index found.
  return roomRateTypeIds.indexOf(room.room_rate_type_id) === index;
});

console.log(newRooms);

但是我还需要确保只有<* c $ c> room_rate_type_id 匹配，但他们的pric即

However I also need to make sure that objects only get removed if not only their room_rate_type_id matches but also their price.

我可以理解过滤器功能在我给出的示例中是如何工作的，但我不确定如何干净地检查价格，最好是在ES6中。

I can understand how the filter functionality works in my given example but I am unsure how to cleanly do a check for the price as well, preferably in ES6.

推荐答案

你可以做到

const rooms = [
  {
    room_rate_type_id: 202,
    price: 200
  },
  {
    room_rate_type_id: 202,
    price: 200
  },
  {
    room_rate_type_id: 202,
    price: 189
  },
  {
    room_rate_type_id: 190,
    price: 200
  }
];

let result = rooms.filter((e, i) => {
    return rooms.findIndex((x) => {
    return x.room_rate_type_id == e.room_rate_type_id && x.price == e.price;}) == i;

});

console.log(result);

这将过滤除第一次出现任何对象之外的所有重复

This would filter all duplicates except the first occurrence of any object

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