字母数：返回重复字母数最多的第一个单词 [英] Letter Count: return the first word with the greatest number of repeated letters

问题描述

任何人都可以帮我解决这个问题吗？这是一个字母计数挑战，您需要返回具有最大重复字母数的第一个单词，例如：Input =Hello apple pie输出= Hello

Can anyone help me out with the bug? This is a letter count challenge that you need to return the first word with greatest number of repeated letters, e.g.: Input = "Hello apple pie" Output = Hello

我试过了调试我的代码的许多不同方法，并注意到字符串没有传递到while循环，但我不知道为什么。任何人都可以解释一下吗？

I tried many different ways to debug my code and notice that the string didn't pass into the while loop, but I have no ideas why. Can anyone explain?

function LetterCount(str) { 
  str = str.split(" ");
  var index = 0;
  while(index >= str.length){
  	for(var i = 0; i < str.length; i++){
      var str1 = str[i].split("").sort();
      for(var k = 0; k < str1.length; k++){
        
      	if(index === 0 && str1[k] === str[k+1]){
          return str[i];
      	}
      	else if(index > 0 && str1[k] === str[k+1]){
          return str[i];
      	}
      }
    }
    index++;
  }
  return -1;
}

推荐答案

这也是一些正则表达式的魔法。 ;）

Here's some regex magic to pull it off as well. ;)

function LetterCount(str) {
    var parts = str.replace(/(\s+)|([A-Z]*?)([A-Z])(\3+)([A-Z]*)|([A-Z]+)/gi, "$1$2$3$4$5$6,$3$4,").split(',');
    var firstIndexOfMaxLetters, maxCount = 0;
    for (var i = 1; i < parts.length; i += 2)
        if (parts[i].length > maxCount)
            { maxCount = parts[i].length; firstIndexOfMaxLetters = i; }
    return firstIndexOfMaxLetters ? parts[firstIndexOfMaxLetters-1] : "";
}
LetterCount("Hi apPple pie")

输出：apPple

正则表达式将字符串转换为：

The regex turns the string into this:

["Hi", "", " ", "", "apPple", "pPp", " ", "", "pie", ""]

...其中数组中的每秒项都是重复的字母（如果有的话，否则为空白），以及这个词在它之前。 ;）

... where every second item in the array is the repeating letters (if any, or blank otherwise), and the word is before it. ;)

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