Node Ramda +根据值查找对象 [英] Node Ramda + find the object based on value

问题描述

可以根据值获取对象吗？

在下面的示例json中，键名具有类型，因此基于类型值需要获取结果。

例如，如果type ='user'，则仅为用户对象而不是员工对象获取结果。

在这里我很难拥有两个密钥（用户和员工），你能否建议如何处理

  var list = [{doc：{type：user，Title：test1，Relations：{users：[{ name：user1}，{name：user2}，{name：user3}]，employee：[{emp：user2}}}}}，{ doc：{type：employee，Title：test2，Relations：{users：[{name：user1}]，employee：[{name ：emp1}，{name：emp2}，{name：emp3}]}}}]; const getDetails = R.chain（R.pipe（R.path（['doc} '，'关系'] ），R.pick（['users'，'employee']），R.values））const result = getDetails（list）console.log（result） 

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当前输出：

  [[{name：user1}，{name：user2}，{name ：user3}]，[{emp：user2}]，[{name：user1}]，[{name：emp1}，{name：emp2 }，{name：emp3}]] 
  

期望输出：

  [[{name：user1}，{name：user2}，{name：user3} ]，[{name：emp1}，{name：emp2}，{name：emp3}]] 
  

解决方案

您可以使用 R.cond 基于一组谓词分支逻辑，例如 type 是否为用户或在您的示例中 employee 。

使用此方法，您需要切换 R.链到 R.map 以匹配您的预期列表，除非您想要额外扁平化数组。

  const list = [{doc：{type：user，Title：test1 ，关系：{用户：[{name：user1}，{name：user2}，{name：user3}]，employee：[{ emp：user2}]}}}，{doc：{type：employee，Title：test2，Relations：{users：[{name： user1}]，employee：[{name：emp1}，{name：emp2}，{name：emp3}}}}}} const getDetails = R.map （R.pipe（R.prop（'doc'），R.cond（[[R.propEq（'type'，'user'），R.path（['Relations'，'users']）]，[ R.propEq（'type'，'employee'），R.path（['Relations'，'employee']）]]）））const expected = [[{n ame：user1}，{name：user2}，{name：user3}]，[{name：emp1}，{name：emp2}， {name：emp3}]] console.log（R.equals（expected，getDetails（list））） 

 < script src =// cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js\"></脚本>  

Possible to get object based on the value?

In below sample json, the key name have type, so based on type value need to fetch the results.

For example if type='user' then fetch the result only for users object not for employee object.

Here I am struggling have both keys(users and employee), Could you please suggest to how to approach

var list =[
  {"doc":{"type":"user","Title":"test1","Relations":{"users":[{"name": "user1"},{"name": "user2"},{"name": "user3"}],"employee":[{"emp": "user2"}]}}},
  {"doc":{"type":"employee","Title":"test2","Relations":{"users":[{"name": "user1"}],"employee":[{"name": "emp1"},{"name": "emp2"},{"name": "emp3"}]}}}
];

const getDetails = R.chain(R.pipe(
  R.path(['doc', 'Relations']),
  R.pick(['users', 'employee']),
  R.values
))

const result = getDetails(list)

console.log(result)

<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script>

Current Output:

[[{"name": "user1"}, {"name": "user2"}, {"name": "user3"}], [{"emp": "user2"}], [{"name": "user1"}], [{"name": "emp1"}, {"name": "emp2"}, {"name": "emp3"}]]

Expecting output:

[[{"name": "user1"}, {"name": "user2"}, {"name": "user3"}], [{"name": "emp1"}, {"name": "emp2"}, {"name": "emp3"}]]

解决方案

You can make use of R.cond to branch logic based on a set of predicates, like whether type is user or employee in your example.

With this approach you will need to switch your R.chain to R.map to match your expected list, unless you want the extra flattening of the arrays.

const list = [
  {"doc":{"type":"user","Title":"test1","Relations":{"users":[{"name": "user1"},{"name": "user2"},{"name": "user3"}],"employee":[{"emp": "user2"}]}}},
  {"doc":{"type":"employee","Title":"test2","Relations":{"users":[{"name": "user1"}],"employee":[{"name": "emp1"},{"name": "emp2"},{"name": "emp3"}]}}}
]

const getDetails = R.map(R.pipe(
  R.prop('doc'),
  R.cond([
    [R.propEq('type', 'user'), R.path(['Relations', 'users'])],
    [R.propEq('type', 'employee'), R.path(['Relations', 'employee'])]
  ])
))

const expected = [[{"name": "user1"}, {"name": "user2"}, {"name": "user3"}], [{"name": "emp1"}, {"name": "emp2"}, {"name": "emp3"}]]

console.log(R.equals(expected, getDetails(list)))

<script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script>

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