分析从服务器的JSON文件 [英] parsing json file from server

问题描述

我上传 JSON 文件到我的服务器。这是 JSON文件但是当我想分析它，它提供了以下错误：

 错误解析数据org.json.JSONException：值小于，java.lang.String类型的DOCTYPE不能转换为JSONObject的！
 

我应该做的服务器，设置？我只设置 MIME 。

您可以在这里审查我的codeS

解决方案

例如响应：

<$p$p><$c$c>{"rows":[{"Fname":"rahim","Lname":"Durosimi","$p$pdictions":"4","C$p$pdictions":"3","Points":"15"},{"Fname":"Otunba","Lname":"Alagbe","$p$pdictions":"5","C$p$pdictions":"2","Points":"10"},{"Fname":"Olamide","Lname":"Jolaoso","$p$pdictions":"4","C$p$pdictions":"2","Points":"10"},{"Fname":"g","Lname":"ade","$p$pdictions":"1","C$p$pdictions":"1","Points":"5"},{"Fname":"Tiamiyu","Lname":"waliu","$p$pdictions":"1","C$p$pdictions":"1","Points":"5"}]}

相当于code您接收字符串的响应之后进行解析。

 的JSONObject JSON =新的JSONObject的（内容）;
JSONArray jArray = json.getJSONArray（行）;
            JSONObject的json_data = NULL;
            的for（int i = 0; I＆LT; jArray.length（）;我++）{
                json_data = jArray.getJSONObject（ⅰ）;
                字符串FNAME = json_data.getString（FNAME）;
字符串LNAME = json_data.getString（L-NAME）;
   }




＆LT; PHP
标题（内容类型：应用程序/ JSON）;
$ CH = curl_init（）;
curl_setopt（$ CH，CURLOPT_URL，您的网址在这里）;
curl_setopt（$沟道，CURLOPT_RETURNTRANSFER，1）;
回声$输出= curl_exec（$ CH）;
curl_close（$ CH）;
？＆GT;
 

I upload a json file to my server. This is the json file but when I want to parse it, it gives the following error:

Error parsing data org.json.JSONException: Value <!DOCTYPE of type java.lang.String cannot be converted to JSONObject

which setting should I do in server? I only set MIME.

You can review my codes here

解决方案

example response:

{"rows":[{"Fname":"rahim","Lname":"Durosimi","Predictions":"4","Cpredictions":"3","Points":"15"},{"Fname":"Otunba","Lname":"Alagbe","Predictions":"5","Cpredictions":"2","Points":"10"},{"Fname":"Olamide","Lname":"Jolaoso","Predictions":"4","Cpredictions":"2","Points":"10"},{"Fname":"g","Lname":"ade","Predictions":"1","Cpredictions":"1","Points":"5"},{"Fname":"Tiamiyu","Lname":"waliu","Predictions":"1","Cpredictions":"1","Points":"5"}]}

equivalent code to parse after you receive the response in string.

JSONObject json = new JSONObject(content);          
JSONArray jArray = json.getJSONArray("rows");
            JSONObject json_data = null;
            for (int i = 0; i < jArray.length(); i++) {
                json_data = jArray.getJSONObject(i);
                String fname = json_data.getString("Fname");
String lname = json_data.getString("Lname");                
   }




<?php
header('Content-Type: application/json');
$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, "your url here"); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
echo $output = curl_exec($ch); 
curl_close($ch);      
?>

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