如何正确运行程序？每当我运行该程序时，它说.exe停止工作。请帮忙 [英] How do I run the programme properly? Whenever I run the programme, it says .exe stopped working. Please help

问题描述

#include<stdio.h>
#include<conio.h>
int main()
{
	int a,b,c;
	
	printf("\nEnter the value of a : ");
	scanf("%d",a);
	
	printf("\nEnter the value of b : ");
	scanf("%d",b);
	
	printf("\nEnter the value of c : ");
	scanf("%d",c);
	
    if(a>b)
	{
		if(a>c)
		printf("\n%d is the largest number",a);
		else
		printf("\n%d is the largest number",c);
	}
	else
	{
		if(b>c)
		printf("\n%d is the largest number",b);
		else
		printf("\n%d is the largest number",c);
	}
}

我的尝试：



当我运行程序时，输入a的值后，它说.exe停止工作。

请帮助我。

What I have tried:

When i run the programme,, after entering value of a, it says, .exe stopped working.
Please help me.

推荐答案

scanf需要您要存储值的变量的地址，而不是内容。所以当你这样写：

scanf requires addresses of the variables you want to store teh values in, not teh content. So when you write this:

int a,b,c;
...
scanf("%d",a);

您传递一个随机值（因为您还没有将任何内容分配给 a ）作为您希望结果放入的地址。所以它确实如此。 ，发现它不存在，你的应用程序崩溃。



当你用C或C ++调用函数时，所有参数都是按值传递的，而不是通过引用传递的 - 制作内容的副本，然后传递内容，而不是说出内容的来源。如果你考虑一下，那是个好主意：

You are passing a random value (since you haven't allocated anything to a yet) as the address you want the result placed in. So it does, finds it doesn't exist, and your app crashes.

When you call a function in C or C++, all parameters are passed by value, not by reference - a copy of the content is made and that is passed rather than something which says where it came from. If you think about it, that is a damn good idea:

void DoSomething(int i)
   {
   i = 1 + 1;
   }

当你这样称呼它时很好：

Is fine when you call it like this:

int val = 666;
DoSomething(val);

Eitehr方式，但如果你这样称呼：

Eitehr way, but if you call it like this:

DoSomething(666);

然后任何按引用传递调用都会给你带来真正的问题，因为常数的值必须改变！



尝试传递 a 的地址而不是值：

Then any "pass by reference" call will give you real problems as the value of a constant number would have to change!

Try passing the address of a instead of the value:

scanf("%d",&a);

and don'忘记 b 和 c ！

And don't forget b and c either!

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