窗口小部件JSON解析后没有更新 [英] Widget is not updating after JSON parse

问题描述

我有以下的code：

  @覆盖
    公共无效的onReceive（上下文的背景下，意图意图）{
        super.onReceive（背景下，意图）;

        如果（CLOCK_WIDGET_UPDATE.equals（intent.getAction（）））{
            Toast.makeText（上下文，onReceiver（），Toast.LENGTH_LONG）.show（）;
        }

        新的getJSON（）执行（NULL，NULL，NULL）;
    }
    公共类的getJSON扩展的AsyncTask＆LT;虚空，虚空，虚空＆GT; {
         @覆盖
         保护无效doInBackground（虚空...... PARAMS）{//在后台运行
             尝试 {
                 HttpClient的=新DefaultHttpClient（新BasicHttpParams（））;
                 HttpPost httppost =新HttpPost（http://pagesbyz.com/hadith.json）;
                 //取决于Web服务
                 httppost.setHeader（内容型，应用/ JSON）;
                HTT presponse响应= httpclient.execute（httppost）;
                HttpEntity实体= response.getEntity（）;

                的InputStream = entity.getContent（）;
                // JSON是UTF-8在默认情况下
                的BufferedReader读卡器=新的BufferedReader（新的InputStreamReader（InputStream中，UTF-8），8）;
                SB =新的StringBuilder（）;

                串线= NULL;
                而（（行= reader.readLine（））！= NULL）
                {
                    sb.append（行+\ N）;
                }
                结果= sb.toString（）;

            }赶上（例外五）{
                Log.i（TEST，e.toString（））;
                //哎呀
            }
            最后 {
                尝试{如果（的InputStream！= NULL）inputStream.close（）;}赶上（例外挤）{}
            }
            返回null;
         }

         @覆盖
         在preExecute（）保护无效{//活动的进展情况
         }

         @覆盖
        保护无效onPostExecute（空V）{
             尝试 {
                 jsonArray =新JSONArray（结果）;
                 日期=新的String [jsonArray.length（）];
                 报价=新的String [jsonArray.length（）];
                 通过=新的String [jsonArray.length（）];
                    的for（int i = 0; I＆LT; jsonArray.length（）;我++）{
                        JSONObject的jsonObj =（的JSONObject）jsonArray.get（我）;
                        日期[i] = jsonObj.getString（日期）;
                        报价[I] = jsonObj.getString（报价）;
                        由[i] = jsonObj.getString（通过）;
                    } //结束循环
                    views.setTextViewText（R.id.tvToday，日期[0]）;
                    views.setTextViewText（R.id.tvParkStatus，报价[0]）;
             }
             赶上（JSONException E）{
                 e.printStackTrace（）;
             }
        }
    }
 

我期待更新从JSON文件接收到的信息的部件。我看小部件，但并未显示信息。

我的JSON是这样的：

  [
    {
        日期：11182013​​，
        报价：今天是星期一，
        本经：SiKni8
    }，
    {
        日期：11192013​​，
        报价：今天是星期二，
        本经：SiKni8
    }
]
 

解决方案

更​​改AsynkTast为：

 公共类的getJSON扩展的AsyncTask＆LT;虚空，虚空，字符串＆GT; {

     @覆盖
     保护无效doInBackground（虚空...... PARAMS）{//在后台运行

     // ...
     //做所有的东西，因为它是和更改回这样的：

     返回结果;
     }

    @覆盖
    保护无效onPostExecute（字符串结果）{
    //留给其他的你code，因为它是。
    }
}
 

和变更执行，以新的getJSON（）执行（）;

I have the following code:

@Override
    public void onReceive(Context context, Intent intent) {
        super.onReceive(context, intent);

        if (CLOCK_WIDGET_UPDATE.equals(intent.getAction())) {
            Toast.makeText(context, "onReceiver()", Toast.LENGTH_LONG).show();
        }

        new GetJSON().execute(null, null, null);
    }
    public class GetJSON extends AsyncTask<Void, Void, Void> {
         @Override
         protected Void doInBackground(Void... params) { //Running in background
             try {
                 httpclient = new DefaultHttpClient(new BasicHttpParams());
                 HttpPost httppost = new HttpPost("http://pagesbyz.com/hadith.json");
                 // Depends on your web service
                 httppost.setHeader("Content-type", "application/json");
                HttpResponse response = httpclient.execute(httppost);           
                HttpEntity entity = response.getEntity();

                inputStream = entity.getContent();
                // json is UTF-8 by default
                BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"), 8);
                sb = new StringBuilder();

                String line = null;
                while ((line = reader.readLine()) != null)
                {
                    sb.append(line + "\n");
                }
                result = sb.toString();

            } catch (Exception e) {
                Log.i("TEST", e.toString());
                // Oops
            }
            finally {
                try{if(inputStream != null)inputStream.close();}catch(Exception squish){}
            }
            return null;
         }

         @Override
         protected  void onPreExecute() { //Activity is on progress
         }

         @Override
        protected void onPostExecute(Void v) {
             try {
                 jsonArray = new JSONArray(result);
                 date = new String[jsonArray.length()];
                 quote = new String[jsonArray.length()];
                 by = new String[jsonArray.length()];
                    for (int i = 0; i < jsonArray.length(); i++) {
                        JSONObject jsonObj = (JSONObject) jsonArray.get(i);
                        date[i] = jsonObj.getString("Date");
                        quote[i] = jsonObj.getString("Quote");
                        by[i] = jsonObj.getString("By");
                    } // End the for loop
                    views.setTextViewText(R.id.tvToday, date[0]);
                    views.setTextViewText(R.id.tvParkStatus, quote[0]);
             }
             catch (JSONException e) {
                 e.printStackTrace();
             }
        }
    }

I am looking to update the widget with the information received from the JSON file. I see the widget but no information is being displayed.

My JSON looks like:

[
    {   
        "Date" : "11182013",
        "Quote" : "Today Is Monday",
        "By" : "SiKni8"
    },
    {   
        "Date" : "11192013",
        "Quote" : "Today Is Tuesday",
        "By" : "SiKni8"
    }
]

解决方案

Change your AsynkTast to:

public class GetJSON extends AsyncTask<Void, Void, String> {

     @Override
     protected Void doInBackground(Void... params) { //Running in background

     // ...
     // do all your stuff as it is and change return to this :

     return result;
     }

    @Override
    protected void onPostExecute(String result) { 
    // left other of your code as it is.
    }
}

And change execution to new GetJSON().execute();

这篇关于窗口小部件JSON解析后没有更新的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！