如何删除此错误？ [英] How to remove this error?

问题描述

#include<stdio.h>
int dot_product(int n,int *aa,int *bb)
{
    int i,j,sum=0,temp;
    for(i=0;i<n;i++)
    {
        for(j=i+1;j<n;j++)
        {
            if(aa[i]>aa[j])
            {
                temp=aa[i];
                aa[i]=aa[j];
                aa[j]=temp;
            }
        }
    }
    for(i=0;i<n;i++)
    {
        for(j=i+1;j<n;j++)
        {
            if(bb[i]<bb[j])
            {
                temp=bb[i];
                bb[i]=bb[j];
                bb[j]=temp;
            }
        }
    }
    for(i=0;i<n;i++)
        sum+=aa[i]*bb[i];
    return sum;
}
int main()
{
    int n,s,i,j;
    scanf("%d",&n);
    int a[n],b[n];
    for(i=0;i<n;scanf("%d",a[i++]));
    for(i=0;i<n;scanf("%d",b[i++]));
    s=dot_product(int n,int a[n],int b[n]);
    printf("%d",s);
    return 0;
}

我的尝试：



错误：对'dot_product'函数的争论太少

What I have tried:

error:too few argiements to function 'dot_product'

推荐答案

查看错误消息：

Look at the error message:

too few argiements to function 'dot_product'

如果你复制'n'pasted错误信息，那就是：

If you had copy'n'pasted the error message, it would have been:

Too few arguments to function 'dot_product'

这让我们的生活变得更轻松，所以试着记住以后 - 有了更复杂的错误信息，它需要精确并复制' n'paste是确保这一点的最好方法。



但是信息非常清楚：你已经定义了一个名为 dot_product 有三个参数：



That makes our lives easier, so try to remember that in future - with more complex error messages, it needs to be exact and copy'n'paste is the best way to ensure that.

But the message is pretty clear: you have defined a function called dot_product which takes three parameters:

int dot_product(int n,int *aa,int *bb)

但是当你调用它时，你指定的数据类型会混淆系统：

But when you call it, you are specifying the datatypes, which confuses the system:

s=dot_product(int n,int a[n],int b[n]);

试试这个s：

Try this:

s=dot_product(n, &(a[n]), &(b[n]));

将元素的地址传递给函数，虽然我认为你要做的是：

Which passes the addresses of the elements to the function, though I think what you are trying to do is this:

s=dot_product(n, a, b);

将指针传递给每个数组的第一个元素。

which will pass the pointer to the first element of each array.

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