使用for循环来跟踪播放的轮次并将用户选择与计算机进行比较 [英] Using a for loop to keep track of rounds played and comparing user choice to computer
问题描述
背景：计算机角色在类中定义。所有输入/输出必须在主功能内部进行。另外，我为标记c ++ 98和14道歉。我不知道这是哪个版本。
< pre lang = c ++> #include< string>
#include< iostream>
using namespace std;
int ROUNDS;
int USER_CHOICE;
int SCORE;
class ComputersChoice {//包含AI播放器随机数函数的类
private：
int randNum = rand（）％5 + 1;
public：
void SetNum（int value）{//由于某些原因，程序在没有此参数的情况下运行缓慢，并将其设置为等于randNum
randNum = value;
}
int GetNum（）{
return randNum;
}
void printResult（）{
if（randNum == 1）{
cout<<计算机选择摇滚。;
}
else if（randNum == 2）{
cout<<计算机选择了纸张。;
}
否则如果（randNum == 3）{
cout<<计算机选择了剪刀。;
}
else if（randNum == 4）{
cout<<计算机选择了蜥蜴。;
}
else {
cout<<计算机选择了spock。;
}
}
};
int main（）{
//用户想玩多少轮？
cout<<你想玩3轮，5轮还是7轮？ << ENDL;
cin>> ROUNDS;
开关（ROUNDS）{
案例3：
cout<<你选择最好的3轮。<< endl ;
休息;
案例5：
cout<<你选择了最好的5轮。<< endl;
休息;
案例7：
cout<<你选择了最好的7轮。<< endl;
休息;
默认值：
cout<<输入无效。输入3,5或7。<< endl;
休息;
}
//用户输入
cout<<输入1表示摇滚，2表示纸张，3表示剪刀，4表示蜥蜴或者5表示spock。<< endl;
cin>> USER_CHOICE;
开关（USER_CHOICE）{
案例1：
cout<<你选择了摇滚乐。 << ENDL ;;
休息;
案例2：
cout<<你选择了纸张。 << ENDL;
休息;
案例3：
cout<<你选择了剪刀。 << ENDL;
休息;
案例4：
cout<<你选择了蜥蜴。 << ENDL;
休息;
案例5：
cout<<你选择了spock。 << ENDL;
休息;
默认值：
cout<<无效输入。输入1表示摇滚，2表示纸张，3表示剪刀，4表示蜥蜴或5表示spock。 << ENDL;
休息;
}
srand（time（NULL））;
//对象创建
ComputersChoice randomNumber;
//获取随机数并相应地打印结果
randomNumber.GetNum（）;
randomNumber.printResult（）;
}
我尝试了什么：
通过循环，我尝试将整个switch语句包装在循环，在switch语句的外部，在case的上方或下方和内部放置一个循环。我完全迷失了如何将计算机的随机数与用户选择进行比较。随机数是在类中生成的，我不确定如何访问随机数。
首先，你需要先在第一个循环上开始用户选择：如果他们输入无效输入，那么它会抱怨，但让他们无论如何都要玩 - 这很糟糕。添加一个有效条目变量，并循环直到你得到一个。
其次，你需要第二个循环来实际游戏的用户输入。这一次，你循环用户选择的轮数：3,5或7.
我这样做的方法是抽象代码函数：从GetRounds函数开始：
int GetRounds（）
{
bool isValid = false ;
int numberRounds = 0 ;
while （！isValid）
{
cout<< 你想玩3轮，5轮还是7轮？<< ENDL;
cin>> numberRounds;
switch （numberRounds）
{
case 3 ：
case 5 ：
case 7 ：
isValid = true < /跨度>;
break ;
默认：
cout<< 输入无效。输入3,5或7。<< ENDL;
break ;
}
}
cout<< 你选择了最好的<< numberRounds<< rounds。<< endl;
return numberRounds;
}
然后从你的Main函数调用它。
添加第二个PlayRound函数 - 你可以自己编写一个 - 并使用for循环来调用用户选择的次数。
让PlayRounds函数返回1以获得玩家获胜， - 1表示计算机获胜，0表示平局，然后将每个结果加起来。最后，正面总数是玩家赢得会议，负面是计算机会议的胜利。
首先尝试，然后看看你得到多远。
Background: The computers role is defined in the class. All input/output must take place inside the main function. Also, I apologize for tagging c++98 and 14. I don't know which version this is.
<pre lang="c++">#include <string>
#include <iostream>
using namespace std;
int ROUNDS;
int USER_CHOICE;
int SCORE;
class ComputersChoice { //Class that contains the random number function for the AI player
private:
int randNum = rand() % 5 + 1;
public:
void SetNum(int value) { //Program runs slow for some reason without this parameter and setting it equal to randNum
randNum = value;
}
int GetNum() {
return randNum;
}
void printResult() {
if (randNum == 1) {
cout <<"The computer chose rock.";
}
else if (randNum == 2) {
cout<<"The computer chose paper.";
}
else if (randNum == 3) {
cout<<"The computer chose scissors.";
}
else if (randNum == 4) {
cout<<"The computer chose lizard.";
}
else {
cout<<"The computer chose spock.";
}
}
};
int main() {
//How many rounds does the user want to play?
cout<<"Do you want to play 3, 5 or 7 rounds?" << endl;
cin>>ROUNDS;
switch(ROUNDS) {
case 3:
cout<<"You picked best of 3 rounds."<<endl;
break;
case 5:
cout<<"You picked best of 5 rounds."<<endl;
break;
case 7:
cout<<"You picked best of 7 rounds."<<endl;
break;
default:
cout<<"Invalid input. Enter 3, 5 or 7."<<endl;
break;
}
//User Input
cout<<"Enter 1 for rock, 2 for paper, 3 for scissors, 4 for lizard or 5 for spock."<<endl;
cin>>USER_CHOICE;
switch(USER_CHOICE) {
case 1:
cout<<"You chose rock." << endl;;
break;
case 2:
cout<<"You chose paper." << endl;
break;
case 3:
cout<<"You chose scissors." << endl;
break;
case 4:
cout<<"You chose lizard." << endl;
break;
case 5:
cout<<"You chose spock." << endl;
break;
default:
cout<<"Invalid input. Enter 1 for rock, 2 for paper, 3 for scissors, 4 for lizard or 5 for spock." << endl;
break;
}
srand(time(NULL));
//Object creation
ComputersChoice randomNumber;
//Fetches the random number and prints results accordingly
randomNumber.GetNum();
randomNumber.printResult();
}
What I have tried:
With the loop I have tried wrapping the entire switch statement in a loop, putting a loop on the outside of the switch statement above or below and inside the cases. I am completely lost on how to compare the random number of the computer to the user choice. The fact the random number is generated in a class, I am unsure how to access the random number.
First off, you need to start by looping on the first user choice: if they enter an "Invalid input" then it complains, but lets them play anyway - that's bad. Add a "valid entry" variable, and loop until you get one.
Second, you need a second loop for the user input of the actual game. This time, you loop for the number of rounds the user selected: 3, 5, or 7.
The way I'd do it, is to abstract the code into functions: start with a GetRounds function:
int GetRounds() { bool isValid = false; int numberRounds = 0; while (!isValid) { cout << "Do you want to play 3, 5 or 7 rounds?" << endl; cin >> numberRounds; switch(numberRounds) { case 3: case 5: case 7: isValid = true; break; default: cout << "Invalid input. Enter 3, 5 or 7." << endl; break; } } cout<<"You picked best of " << numberRounds << " rounds."<<endl; return numberRounds; }
Then call that from your Main function.
Add a second "PlayRound" function - you can write that one yourself - and use aforloop to call it the number of times that the user selected.
Make the PlayRounds function return 1 for player win, -1 for computer win, and 0 for a draw, then add up each result. At the end, a positive total is a player win for the session, negative is a computer session victory.
Start by trying that, and see how far you get.
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