如何在javascript中以HH：MM：SS格式区分两个日期？ [英] How to get difference between 2 dates in HH:MM:SS format in javascript ?

问题描述

如何区分两种日期格式：HH：MM：SS





假设[从日期] = 03 -04-2017 08:00:00（这是dd-MM-yyyy hh：mm：ss格式）

[迄今] = 04-04-2017 09:00:00（这个是dd-MM-yyyy hh：mm：ss格式）





现在输出将是:( todate -from date） = 25:00:00



如何获得这个价值？



请帮忙。我试了很多次。但没有找到任何解决方案。



我尝试过：



var from_date = new Date（03-04-2017 08:00:00）;

var to_ = new Date（04-04-2017 09:00:00）;

alert（now）;

alert（then）;

how to get difference between 2 dates in the format : HH:MM:SS


suppose [ from date ]= 03-04-2017 08:00:00 (this is in dd-MM-yyyy hh:mm:ss format)
[ to date ]=04-04-2017 09:00:00 (this is in dd-MM-yyyy hh:mm:ss format)


now the output will be : (todate -from date) = 25:00:00

how to get this value ?

please help . i tried a a lot. but didn't find any solutions.

What I have tried:

var from_date =new Date( "03-04-2017 08:00:00");
var to_=new Date( "04-04-2017 09:00:00");
alert(now);
alert(then);

推荐答案

function getDateObject(datestr) {
          var parts = datestr.split(' ');
          var dateparts = parts[0].split('-');
          var day = dateparts[0];
          var month = parseInt(dateparts[1]) - 1;
          var year = dateparts[2];
          var timeparts = parts[1].split(':')
          var hh = timeparts[0];
          var mm = timeparts[1];
          var ss = timeparts[2];
          var date = new Date(year, month, day, hh, mm, ss, 00);
          return date;
      }

      function gettimediff(t1, t2) {
          var t1val = Number( t1.getHours() * 60 + t1.getMinutes());
          var t2val = Number(t2.getHours() * 60 + t2.getMinutes());
          var min = Math.floor((t2val - t1val) % 60);
          var hours = parseInt((t2 - t1) / (1000 * 60 * 60));
          return (hours + ':' + min + ':00');
      }

      var from = '03-04-2017 08:00:00';
      var to = '04-04-2017 09:00:00';
      from = getDateObject(from);
      to = getDateObject(to);

      alert(gettimediff(from, to)); //25:0:00

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