为什么我的后续子例程会抛出错误? [英] Why my following sub routine throws an error?
本文介绍了为什么我的后续子例程会抛出错误?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
syntax error at Script line 19, near "queue_name)" syntax error at Script line 39, near "}" Script had compilation errors. syntax error at /proj/in/db.cgi line 879, near "queue_name)"
我尝试过:
What I have tried:
<pre>sub print_overall_summary
{
my $str = shift;
$DBH = &connect or die "Cannot connect to the sql server \n";
$DBH->do("USE $str;");
my $stmt="select queue_name,jobs_pending,jobs_running from queues order by time desc ;";
;
my $sth = $DBH->prepare( $stmt );
$sth->execute() or print "Could not prepare_overall_summarydata";
print "<script language=\"javascript\" type=\"text/javascript\"> \n"
;
print "\$(document).ready(function(){ \n";
%TABLE_DATA =();
my @sys=qw/Adice Incisive Spectre Vcs Calibre Others/;
my $table = $sth->fetchall_hashref;
for my $r (@$table) {
my $name='Others';
for my $s (@sys){
if ($r->{queue_name)=~m/$s/i) {$name=$s; last;}
}
$TABLE_DATA{$name}{jobs_pending}+=$r->{jobs_pending};
$TABLE_DATA{$name}{jobs_running}+=$r->{jobs_running};
}
for my $var(qw/running pending/) {
my @parts=();
for my $s (@sys){
push @parts,'["'.$s.'",'
.$TABLE_DATA{$s}{'jobs_'.$var}
.']';
}
print 'var data_'.$var.'=['.join(',',@parts).']'."\n";
}
print " \n pieChart(\"placeholder39\",data_running,{title:\"<ce
nter>Jobs Running</center>\"});\n";
print " \n pieChart(\"placeholder41\",data_pending,{title:\"<ce
nter>Jobs Pending</center>\"});\n";
print "});";
print "</script>";
}
推荐答案
str = shift;
str = shift;
DBH =& connect or die无法连接到sql server \ n;
DBH = &connect or die "Cannot connect to the sql server \n";
DBH-> do(USE
DBH->do("USE
这篇关于为什么我的后续子例程会抛出错误?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文