Cin跳过并且不要求价值 [英] Cin skips and don't ask for value

问题描述

class Order {
public:
	char customer[99];
	int numofOrd;
	int code[5];
	int quantity[5];

	void addOQ();
	bool updateOQ();
	void viewOQ();
};Order O[99];

void Order::addOQ() {
	char yn = 'y';
	cout << "Costumer Number " << orderNum;
	cout << "\nEnter customer name: ";
	cin >> O[orderNum].customer[99];
	cin.ignore('\n');
	
	for (int i = 1; tolower(yn) == 'y'; i++) {
		O[orderNum].numofOrd++;
		cout<< orderNum;
		cout << "Enter product code: ";
		cin >> O[orderNum].code[numofOrd];
			
		cout << "Enter quantity: ";
		cin >> O[orderNum].quantity[numofOrd];
		
		cout << "\nOrder added to queue\n";
		cout << "Add more?(Y|N)";
		cin >> yn;
	}
}

我的尝试：



它跳过询问代码和数量

这有什么问题吗？

当我把cin.ignore的值设为值' t存储在变量

What I have tried:

It skips asking the code and quantity
what is wrong in this?
when i put cin.ignore the value doesn't store in the variable

推荐答案

获取输入的循环具有测试yn等于'y'的条件，你用'y'初始化yn因此条件为真，循环甚至不执行一次。

The loop that gets the input has the condition to test yn equal to 'y', you initialise yn with 'y' therefore the condition is true and the loop does not execute even once.

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