为什么闭合支架是黑色的？ [英] Why is the closing bracket black ?
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问题描述
你好，
在我的NotePad ++上，116处的行显示了ELSE黑色的右括号。真的很令人费解！
我知道我的代码不是很整洁但是我会根据我到目前为止的反馈来整理它但同时我的脑子里充满了为什么116线的问题显示ELSE黑色的右括号。
Howdy,
On my NotePad++, the line at 116 shows the closing bracket of the ELSE black. Really really puzzling!
I know my code is not neat but I will tidy it up based on the feedback I got so far but in the meanwhile my great mind is filled with the question why the line at 116 shows the closing bracket of the ELSE black.
<html>
<head>
<title>
$user Home Page
</title>
</head>
<body>
<body background=".png">
<?php
session_start();
require "conn.php";
/*Check if user is logged-in or not by checking if session is set or not.
If user is not logged-in then redirect to login page. Else, show user's account homepage.*/
if(!isset($_SESSION["user"]))
{
header("location:login.php");
}
else
{
$user = $_SESSION["user"];
$sql = "SELECT * FROM users WHERE Username = '".$user."'";
$result = $conn->query($sql);
while($row = mysqli_fetch_assoc($result))
{
$db_id = $row["Id"];
$db_username = $row["Username"];
$db_forename = $row["Forename"];
$db_surname = $row["Surname"];
$db_email = $row["Email"];
$db_bio = $row["Bio"];
$db_status = $row["Status"];
//Welcome user by name.
echo "<center>Welcome <h2>$db_forename $db_surname!</center>"?></h2>|
<?php
//Display log-out link.
echo "<p align='right'><a href='logout.php'>$user Log Out</a>";?>|</p><br>
<form method="post" action="">
<div class="form-group">
<center><label>Post Status To Friends:</label>
<input type="text" placeholder="Post Status To Friends" name="post_status_to_friends" /></center><br>
<center><button type="submit" class="btn btn-default" name="post_status_to_friends" />Post Status To Friends!</button></center>
</div>
<form method="post" action="">
<div class="form-group">
<center><label>Post Status To Public:</label>
<input type="text" placeholder="Post Status To Public" name="post_status_to_public" /></center><br>
<center><button type="submit" class="btn btn-default" name="post_status_to_public" />Post Status To Public!</button></center>
</div>
<?php
//Post User Status To Friends in $user table.
if (isset($_POST['post_status_to_friends']))
{
$status_to_friends = trim($_POST["post_status_to_friends"]);
$status_to_friends = mysqli_real_escape_string($conn,$status_to_friends);
$conn->query("UPDATE $user SET Status_To_Friends $status_to_friends WHERE Username = '".$user."'");
if($conn->query($sql)===TRUE)
{
echo "posted status for friends to $user table!";
$conn->close();
exit();
}
else
{
echo "posting status for friends to $user table failed!";
$conn->close();
exit();
}
//Post User Status To Friends in "users" table.
$conn->query("UPDATE users SET Status_To_Friends $status_to_friends WHERE Username = '".$user."'");
if($conn->query($sql)===TRUE)
{
echo "posted status for friends to users table!";
$conn->close();
exit();
}
else
{
echo "posting status for friends to users table failed!";
$conn->close();
exit();
}
//Display User Status To Friends. Search for User's data with $user.
$query = "SELECT * FROM $user WHERE Username = '".$user."'";
$result = mysqli_query($conn,$query);
$numrows = mysqli_num_rows($result);
if($numrows = 0)
{
echo "No data!";
$conn->close();
exit();
}
else
{
while($row = mysqli_fetch_assoc($result))
{
$db_status_to_friends = $row["Status_To_Friends"];
}
echo "<br>$user Status To Friends:<br>
$db_status_to_friends";?><br>
<br>
}
<?php
//Post User Status To Public in $user table.
if (isset($_POST['post_status_to_public']))
{
$status_to_public = trim($_POST["post_status_to_public"]);
$status_to_public = mysqli_real_escape_string($conn,$status_to_public);
$conn->query("UPDATE $user SET Status_To_Public $status_to_public WHERE Username = '".$user."'");
if($conn->query($sql)===TRUE)
{
echo "posted status for public to $user table!";
$conn->close();
exit();
}
else
{
echo "posting status for public to $user table failed!";
$conn->close();
exit();
}
//Post User Status To Public in users table.
$conn->query("UPDATE users SET Status_To_Public $status_to_public WHERE Username = '".$user."'");
if($conn->query($sql)===TRUE)
{
echo "posted status for public to users table!";
$conn->close();
exit();
}
else
{
echo "posting status for public to users table failed!";
$conn->close();
exit();
}
//Display User Status To Public. Search for User's data with $user.
$query = "SELECT * FROM $user WHERE Username = '".$user."'";
$result = mysqli_query($conn,$query);
$numrows = mysqli_num_rows($result);
if($numrows = 0)
{
echo "No data!";
$conn->close();
exit();
}
else
{
while($row = mysqli_fetch_assoc($result))
{
$db_status_to_public = $row["Status_To_Public"];
}
echo "<br>$user Status To Public:<br>
$db_status_to_public";?><br>
<br>
<?php
}
}
//Display User Bio.
echo "<br>Bio:<br>";
echo "$db_bio";?><br>
<br>
<?php
//Display User's Latest View.
echo "<br>Latest View:<br>";
echo "$db_latest_view";?><br>
<br>
<?php
//Display User's Latest Viewed Url in iFrame.?>
<iframe src="<?php $db_latest_view;?>"></iframe>
<?php
}
}
?>
</body>
</html>
我尝试过：
尝试用不同的方式改变代码，但没有运气！
What I have tried:
Tried changing code many different ways but no luck!
推荐答案
用户主页
< / title >
< ; / head >
< body >
< body background = 。png >
<？ php
session_start（）;
需要 conn.php;
/ * 通过检查会话是否已设置或检查用户是否已登录不。
如果用户未登录，则重定向到登录页面。否则，显示用户的帐户主页。* /
if（！isset（
user Home Page </title> </head> <body> <body background=".png"> <?php session_start(); require "conn.php"; /*Check if user is logged-in or not by checking if session is set or not. If user is not logged-in then redirect to login page. Else, show user's account homepage.*/ if(!isset(
_SESSION [ user]））
{
header（ < span class =code-string> location：login.php）;
}
else
{
_SESSION["user"])) { header("location:login.php"); } else {
user =
user =
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