我必须输入允许空格的28个字符的验证，如果我们输入任何超过28个字符的名字，它应该拒绝那个 [英] I have to enter a validation for 28 character which allows white space and if we enter any name having more then 28 char, it should rather reject that

问题描述

[A-Za-z0-9 _ @。/＃& + - \ / s] {0,28}/>

但这允许空格但不会t拒绝拥有超过28个字符的名称，而不是截断它，并且只允许28个字符。



我尝试过：



[A-Za-z0-9 _ @。/＃& + - \ / s] {0,28}/>

解决方案

您的模式中存在一些错误。



- 减号定义括号内的字符类中的范围。因此，如果要匹配角色，则必须进行转义或第一个角色。当意图使用 + - \ / 时它会匹配从0x2b到0x2f的所有字符（包括可以删除的点）。



最后 s 是没用的。



To允许空格必须 \s 。

[/ EDIT]



要检查有效长度，您必须使用 ^ 和




。



您尚未指定使用的语言。这是一个有效的Perl正则表达式：

 ＃ 编辑：带有空格 
 ＃ 范围从+到/  
 ＃  if（




test =〜/ ^ [A-Za-z0- 9 _ @＃&安培; + - \ / \s] {0,28}

"[A-Za-z0-9_@./#&+-\/s]{0,28}"/>
but this allows white space but doesn't reject name having more then 28 char rather it truncates that and allows only 28 char for the same .

What I have tried:

"[A-Za-z0-9_@./#&+-\/s]{0,28}"/>

解决方案

There are some mistakes in your pattern.

The - minus sign defines a range within a bracketed character class. So it has to be escaped or the first character if you want to match the character. When using +-\/ by intention then it matches all characters from 0x2b to 0x2f (which includes the dot which can then be removed).

The s at the end is useless.
[EDIT]
To allow white spaces it must be \s.
[/EDIT]

To check for valid lengths you have to match the whole string using ^ and




.

You have not specified which language you are using. Here is a working Perl regex:

# Edit: With white spaces
# With range from + to /
#if (

test =~ /^[A-Za-z0-9_@#&+-\/\s]{0,28}

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