最后一个printf（“％s”，* title [5]）;没有输出，为什么？ [英] The last printf("%s", *title[5]); isn't coming in output, why?

问题描述

#include<stdio.h>
int main()
{
char title[]={"tale of 2 cities","wuthering heights","don quixote","odyssey","moby dick","hamlet","gulliver travel"};
charbestbooks[3];
charenglishbooks[4];
bestbooks[0]=&title[0];
bestbooks[1]=&title[3];
bestbooks[2]=&title[5];
englishbooks[0]=&title[0];
englishbooks[1]=&title[1];
englishbooks[2]=&title[5];
englishbooks[3]=&title[6];
printf("%s\n",englishbooks[2]);
englishbooks[2]="changed";
printf("%s\n",*englishbooks[2]);
printf("%s",*title[5]);
return 0;
}

我的尝试：



最后一个printf也应该显示输出：changed。

What I have tried:

the last printf should also display output:"changed".

推荐答案

：叹气：

请看看我对你的最后一个答案，并试着想一想你在做什么。

你展示的代码将无法编译：

:sigh:
Please, look at my last answer to you and try to think about what you are doing.
The code you show won't compile:

char title[]={"tale of 2 cities","wuthering heights","don quixote","odyssey","moby dick","hamlet","gulliver travel"};

不对：这是一个字符数组 - 或一个字符串 - 你试图将它预设为任何字符串数组。它必须是：

Isn't right: thats an array of chars - or a string - and you are trying to preset it to any array of strings. It needs to be:

char* title[]={"tale of 2 cities","wuthering heights","don quixote","odyssey","moby dick","hamlet","gulliver travel"};

然后你的printf仍然赢了;工作：

But then your printf still won;t work:

printf("%s",*title[5]);

因为title是一个指向字符的指针数组（如果你愿意，还是一个字符串数组），所以title [5]是一个指针to char或string，* title [5]是一个char - 但是你告诉printf它是一个指针，所以最好你得到一个分段错误。

试试

because title is an array of pointers to characters (or an array of strings if you prefer) and so title[5] is a pointer to a char, or a string, and *title[5] is a char - but you tell printf it's a pointer, so at best you'd get a segmentation fault.
Try

printf("%s",title[5]);

请仔细看看你在做什么，并尝试将代码翻译成英文 - 你传递的内容变得非常明显。

and please, look carefully at what you are doing and try translating the code into English in your head - it becomes pretty obvious what you are passing.

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