我如何观察（调试）布尔值 [英] How do I watch (debug) boolean values

问题描述

我有以下代码，我不明白为什么P4（3,7）给出返回值true（1），因为这里7（ConTemp.XYCoord [1]）大于5（ReCoordRo.XYCoord [1] ]），所以我想知道一种方法来监控布尔Rechteck1.contains（P4），看窗口不给我这个选项，所以我该如何去做呢？ Thx

I have the following code and i don`t understand why P4(3,7)is giving returnvalue true (1) , since here 7(ConTemp.XYCoord[1]) is bigger than 5 (ReCoordRo.XYCoord[1]), so i would like to know a way to monitor the boolean Rechteck1.contains(P4), watch windows doesnt give me that option, so how do i go about it ? Thx

<pre>#include <iostream>
#include <array>

 using namespace std;
    class Punkt {
        public: int XYCoord [2]={};
        void setupCoord (int x, int y){
            XYCoord[0]=x;
            XYCoord[1]=y;
        }
    };
    class Rechteck {
        public: Punkt ReCoordLu,ReCoordRo;

        double flaeche(double x, double y){
            double xy=x*y;
            return xy;
            }
        bool contains ( Punkt &p){
            Punkt *ConTemp1=&p;
            Punkt ConTemp ;
            ConTemp = *ConTemp1;

            if (ConTemp.XYCoord[0]>=ReCoordLu.XYCoord[0]&&ConTemp.XYCoord[1]<=ReCoordRo.XYCoord[1]){
                return true;}
            else{
                return false;}
                };
        bool contains (Rechteck &){
            if (1){
                return true;}
            else
                return false;
            }
        };
int main()
{/* Rechteck sharedRectangle (Rechteck a , Rechteck b){
            Rechteck c;
            return Rechteck c;
            } */

        Punkt P1,P2,P3,P4;
        P1.setupCoord(1,1);
        P2.setupCoord(5,5);
        P3.setupCoord(3,3);
        P4.setupCoord(3,7);
        Rechteck Rechteck1;
        Rechteck1.ReCoordLu.setupCoord(3,3);
        Rechteck1.ReCoordRo.setupCoord(9,9);
Rechteck1.contains(P4) 

        cout<<"hello"<<P2.XYCoord[0]<<Rechteck1.ReCoordLu.XYCoord[0]
        <<Rechteck1.flaeche(5,5)<<Rechteck1.contains(P4) ;

        return 0;};

我尝试过：



监视窗口，调用堆栈窗口

What I have tried:

watch windows , call stacks windows

推荐答案

嗯。

看看你的包含方法：

Um.
Look at your contains method:

bool contains (Rechteck &){
    if (1){
        return true;}
    else
        return false;
    }

它总是返回 true 因为1是一个非零常数，任何非零值都是真 C / C ++

It always returns true because 1 is a non-zero constant and any nonzero value is "true" in C / C++

问题解决了！它实际上看起来像是我误解了Rechteck1.ReCoordLu.setupCoord（3,3）和

Rechteck1.ReCoordRo.setupCoord（ 9,9）

Problem solved !It actually works looked like i just mistook Rechteck1.ReCoordLu.setupCoord(3,3)with
Rechteck1.ReCoordRo.setupCoord(9,9)

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使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量，这是一个令人难以置信的学习工具。



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调试器在这里向您展示您的代码在做什么你的任务是与它应该做的事情进行比较。

调试器中没有魔法，它没有发现错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。

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