如何使用C＃清除arduino中的串行数据？ [英] How to clear serial data in arduino using C#?
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问题描述
大家好，我现在正在和C＃和Arduino一起工作。我想从C＃表单应用程序中的文本框中发送两个或更多数据。到串口监视器。但我的串口只读取第一个数字，其他数字没有看到。串口读取后，我搜索了一些清除名字。但我没有找到任何符合我目标的东西。我的c＃代码：
Hi everybody, I'm working C# and Arduino at now. I want to send two or more data from textboxes in C# form app. to serial monitor. But my serial port read only first number and other numbers was not seen. I searched some to clear first name after when serial port read. But I didn't find anything for my aim. My c# code :
private void btnSend_Click(object sender, EventArgs e)
{
if (serialPort1.IsOpen)
{
int MyInt = Convert.ToInt32(textBox1.Text);
byte[] b = BitConverter.GetBytes(MyInt);
serialPort1.Write(b, 0, 4);
if (MyInt == 3)
{
Form DataSend = new Form();
DataSend.BackColor = Color.Empty;
DataSend.Text = "DATA SEND";
DataSend.Show(); // ya da ShowDialog();
DataSend.Cursor = Cursors.Hand;
DataSend.StartPosition = FormStartPosition.CenterScreen;
Button btn = new Button();
btn.Text = "Send Again";
btn.Name = "btnSendAgain";
btn.Location = new Point(100,50);
btn.Click += btn_Click;
TextBox txbox = new TextBox();
txbox.Text = "";
txbox.Name = "txtNumber2";
txbox.Location = new Point(100,20);
DataSend.Controls.Add(btn);
DataSend.Controls.Add(txbox);
}
}
else
{
MessageBox.Show("Please check your connction maybe serial port is not connected");
}
}
void btn_Click(object sender, EventArgs e)
{
int MyInt = Convert.ToInt32(textBox1.Text);
byte[] b = BitConverter.GetBytes(MyInt);
serialPort1.Write(b, 0, 4);
}
我的arduino代码：
My arduino code:
<pre>int led = 12;
int num1;
int data[4];
void setup()
{
Serial.begin(9600);
pinMode(led, OUTPUT);
}
void loop()
{
if (Serial.available())
{
num1 = Serial.read();
for (int i = 0; i < 2; i++)
{
data[i] = num1;
}
switch (num1)
{
case 1:
openCloseThree();
break;
case 2:
openCloseTwice();
break;
case 3:
openCloseIwanted();
break;
default:
break;
}
}
}
void openClose()
{
for (int i = 0; i < 1; i++)
{
delay(500);
digitalWrite(led, HIGH);
delay(500);
digitalWrite(led, LOW);
}
}
void openCloseTwice()
{
for (int i = 0; i < 2; i++)
{
delay(500);
digitalWrite(led, HIGH);
delay(500);
digitalWrite(led, LOW);
}
}
void openCloseThree()
{
for (int i = 0; i < 3; i++)
{
delay(500);
digitalWrite(led, HIGH);
delay(500);
digitalWrite(led, LOW);
}
}
void openCloseIwanted()
{
for (int i = 0; i < num1; i++)
{
delay(500);
digitalWrite(led, HIGH);
delay(500);
digitalWrite(led, LOW);
}
}
我尝试过：
实际上我想这样：当我用C＃发送3时，另一个表格打开并再次写入任何数字，我的指示是开放的，直到我写的最后一个数字。
What I have tried:
Actually I want to that: When I send 3 using C#, another form is open and again I write any number, my led is open close until last number that I write.
推荐答案
目前尚不清楚你真正想做什么。无论如何，请注意：
- 在您的C＃代码中，如果您在TextBox中输入
1然后将四个字节发送到串行线：三个0s和一个1（你的Arduino代码不会处理0）。- 在你的Arduino代码中，你没有检查是否
Serial.read（）返回-1（即没有可用数据）。
It is not clear what do you really want to do. Anyway, please note:
- In your C# code, if you enter, for instance,
"1"in your TextBox then four bytes are sent to the serial line: three0s and a single1(the0s won't be handled by your Arduino code).- In your Arduino code you didn't check if
Serial.read() returns-1(i.e. no data available).
我的Arduino部分：
My Arduino part:
<pre>int number[3];
int n;
int i = 0;
int led = 12;
int led2=7;
void setup() {
// put your setup code here, to run once:
Serial.begin(9600);
pinMode(led, OUTPUT);
}
void loop() {
// put your main code here, to run repeatedly:
if (Serial.available() > 0) {
// read the incoming byte:
n = Serial.read();
if (i < 3)
{
number[i] = n;
switch (number[0])
{
case 1:
openClose();
break;
case 2:
openCloseTwice();
break;
case 3:
if (i == 2)
{
for (int j = 0; j < number[1]; j++)
{
delay(500);
digitalWrite(led, HIGH);
delay(500);
digitalWrite(led, LOW);
}
delay(500);
for (int k = 0; k < number[2]; k++)
{
delay(500);
digitalWrite(led2, HIGH);
delay(500);
digitalWrite(led2, LOW);
}
}
break;
default:
break;
}
i++;
}
else
{
i = 0;
}
}
}
void openClose()
{
for (int i = 0; i < 1; i++)
{
delay(500);
digitalWrite(led, HIGH);
delay(500);
digitalWrite(led, LOW);
}
}
void openCloseTwice()
{
for (int i = 0; i < 2; i++)
{
delay(500);
digitalWrite(led, HIGH);
delay(500);
digitalWrite(led, LOW);
}
}
我的c＃部分：
My c# part:
if (serialPort1.IsOpen)
{
int MyInt = Convert.ToInt32(textBox1.Text);
byte[] b = BitConverter.GetBytes(MyInt);
serialPort1.Write(b, 0, 1);
int MyInt2 = Convert.ToInt32(textBox2.Text);
byte[] z = BitConverter.GetBytes(MyInt2);
serialPort1.Write(z, 0, 1);
int MyInt3 = Convert.ToInt32(textBox3.Text);
byte[] p = BitConverter.GetBytes(MyInt3);
serialPort1.Write(p, 0, 1);
}
else
{
MessageBox.Show("Please control your connection");
}
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