如何创建子菜单并为其定义索引 [英] How to create a sub menu and define an index for it
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问题描述
大家好,
我对Visual Basic 6.0的菜单编辑器有问题。
当我想制作菜单时菜单编辑器,我插入一些项目,我
得到以下消息:
*菜单控件数组元素必须有索引..
当我给它是一个数字,子菜单项给出以下消息
*菜单控件数组元素必须是连续的并且在同一个
子菜单中。
Plz提供帮助....
谢谢
我尝试过什么:
目前的菜单是:
mnuFile
....& Login
....& Exit
mnuNew ----> (导航到表格)
....& Company
....& Section
....&新信
mnuReport ---> (导航到datareports)
....& SalesTax
........回复制作
.. ......回复制作
....& IncomTax
........回复制作>
........回复制作
....& About
解决方案
< blockquote>这里: VB菜单 - 在Visual Basic 6中使用菜单 [ ^ ]
Hi All, I have a problem with the Menu Editor of Visual Basic 6.0.. When I want to make a menu with the Menu Editor, and I insert some items, I get the following message: * Menu control array element must have an index.. When I give it a number the the Sub menu items gives the following message * Menu control array elements must be contiguous and within the same submenu. Plz provide help.... Thanks
What I have tried:
my current menus are:
mnuFile
....&Login
....&Exit
mnuNew ----> (navigate to the forms)
....&Company
....&Section
....&New-Letter
mnuReport ---> (navigate to the datareports)
....&SalesTax
........Reply-Made
........Reply-To-Be-Made
....&IncomTax
........Reply-Made
........Reply-To-Be-Made
....&About
解决方案
Here: VB Menu - Working with Menus in Visual Basic 6[^]
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