动态地将内存分配给链表中的字符串 [英] Dynamically allocating memory to a string in a linked list

问题描述

我已经编写了下面的代码但是无法获得预期的输出。



//程序开始

选项= 1

名称=样品



//输出

NULL



我尝试过：

I have written the code below but am not able to get the intended output.

//Program Start
Option = 1
Name = Sample

//Output
NULL

What I have tried:

struct node{
    char *name;
    struct node *link;
};

struct node *head, *temp, *ptr;

void getNameStart(){
    temp = (struct node *) malloc (sizeof(struct node));

    temp -> name = DynamicName();
    temp -> link = head;
    head = temp;
}

void Print(){
    temp = head;
    while(temp != 0){
        printf("\n%s", temp -> name);
        temp = temp -> link;
    }
}

void DynamicName(){
    char *name, c;
    int i=0, j=2;

    fflush(stdin);
    printf("\nEnter name : ");
    c = getchar();
    name = (char *) malloc (sizeof(char));

    while(c != '\n'){
        name[i] = c;
        name = (char *) realloc (name, sizeof(char) * j);
        c = getchar();
        i++, j++;
    }
    name[i] = '\0';
    return name;
}

int main(){
    head = 0;
    int i=0, op1;
    char op[5];

    do{
        printf("\nSelect option : ");
        printf("\n\n1. Insert at beginning\n2. Insert at end\n3. Insert anywhere");
        printf("\n\nYour choice : ");
        scanf("%d", &op1);

        switch (op1){
            case 1 : getNameStart(); break;
        }

        printf("\nInsert more nodes? : ");
        fflush(stdin);
        gets(op);

    }   while(strcmp(op, "YES")==0 || strcmp(op, "yes")==0);

    printf("\n\nThe list is : ");
    Print();
}

推荐答案

Quote：

我发现了问题，

即使你发现了什么问题，也应该考虑学习使用调试器的建议。



当你不理解你的代码在做什么或为什么它做它的作用时，答案是调试器。

使用调试器看看你的代码在做什么。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量，这是一个令人难以置信的学习工具。



调试器 - 维基百科，免费的百科全书 [ ^ ]

掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]



调试器在这里显示你的代码正在做什么，你的任务是与它应该做什么进行比较。

调试器中没有魔法，它没有发现错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。

Even if you have found what was the problem, The advice of learning to use a debugger is something to consider.

When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool.

Debugger - Wikipedia, the free encyclopedia[^]
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]

The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

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