通过除以两个int得到一个double [英] Get a double by dividing two int

问题描述

这可能看起来非常基本......几乎羞于问道。



但我希望通过将整数除以另一个整数得到一个双精度数。



我想这样做0.8



但是我注意到它没有返回4/5我只试过：


p $ p>双倍得分;
得分= 4/5 * 100;

解决方案

 double score =（double）4 /（double）5 * 100; 
 

这也应该有效

  double 得分=（ double ）4/5 *  100 ; 

this may seemed very basic...almost ashamed to asked.

But I want to get a double by dividing an integer by another integer.

I want to 0.8 by doing this

but I notice it is not returning the 4/5 only whole numbers.

What I have tried:

double score;
             score = 4/5*100;

解决方案

double score = (double)4 / (double)5 * 100;

This should work too

double score= (double)4/5 * 100;

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