Trackpopupmenu访问冲突读取位置C ++ [英] Trackpopupmenu access violation reading location C++

问题描述

我想在对话框中的任意位置右键单击弹出菜单



我在资源中创建了一个菜单


使用带有菜单的TrackPopupMenu时
我正在瘦窗口



和使用子菜单时我收到了这个错误



我尝试过：

I wanted to show popup menu on right click anywhere in the dialog

I created one menu in resource

while using the TrackPopupMenu with menu I'm getting thin window

and while using with submenu I'm getting that error

What I have tried:

void CMenuPraticeDlg::OnContextMenu(CWnd* pWnd, CPoint point)
{
	
	GetCursorPos(&point);
	CMenu menu;
    VERIFY(menu.LoadMenu(IDR_MENU_POPUP));
    CMenu *pSub = menu.GetSubMenu(1);
    // Modify menu items here if necessary (e.g. gray out items)
//Here I'm getting error
    int nCmd = pSub->TrackPopupMenuEx(
        TPM_LEFTALIGN | TPM_RIGHTBUTTON | TPM_VERPOSANIMATION | TPM_RETURNCMD | TPM_NONOTIFY,
        point.x, point.y, AfxGetMainWnd(), NULL);
    if (nCmd)
        SendMessage(WM_COMMAND, nCmd);

}

POINT pt;
//getting the current cursor point
GetCursorPos(&pt);
//Here I'm getting thin window
menu.TrackPopupMenu( TPM_LEFTALIGN | TPM_RIGHTBUTTON,pt.x,pt.y,this );

推荐答案

错误可能在这一行

The error is probably in this line

CMenu *pSub = menu.GetSubMenu(1);

何时从资源加载的菜单只包含一个弹出菜单（这是常见的情况） GetSubMenu（）返回 NULL 。



所以改为通过仓位 0 。





当使用 TrackPopupMenu [ex] 时，菜单必须是通过调用 CMenu检索的弹出菜单:: GetSubMenu（）或者是使用 CMenu :: CreatePopupMenu 创建的。使用普通菜单无效。

[/ EDIT]

When the menu loaded from the resources contains only one popup menu (which is a common case) GetSubMenu() returns NULL.

So pass the position 0 instead.


When using TrackPopupMenu[Ex], the menu must be a popup menu retrieved by calling CMenu::GetSubMenu() or having been created using CMenu::CreatePopupMenu. Using a normal menu will not work.
[/EDIT]

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