Converrt psceusdo代码为8086汇编语言 [英] Converrt psceusdo code to 8086 assembly language

问题描述

i=0
while (i<n)
{
if (a==0){
b[i]=c[i]+1;
i++;
a=1;
}
else{
b[i]=c[i+1]+1;
i++;
a=0;
}
}

我的尝试：

What I have tried:

.MODEL small
.STACK
.DATA
N db 4h 
c db 1h,2h,3h
b db 1h,2h,3h,4h
.CODE
.STARTUP
MOV CX,00h
mov cl,N 
mov bl,offset c
clc 
addition:
 mov al,bl
 adc al,0h
 clc
 loop1:
  cmp al,0
 je next1
 next1: add al,1
 mov B[di],al
 inc si 
 inc di
 mov al,1

 loop2:
 cmp al,0
 jnz next2
next2: add al,1
 mov B[di],al
 inc si
 inc di
 mov al,0

 loop addition 
 .EXIT
 END

推荐答案

当你不理解你的代码在做什么或为什么它做它的作用时，答案是调试器。

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调试器中没有魔法，它没有发现错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。

When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute, it is an incredible learning tool.

Debugger - Wikipedia, the free encyclopedia[^]
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The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

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