如何使用C ++中的结构编写此问题 [英] How do I code this question using structures in C++
问题描述
1。创建板球比赛。将有两支球队相互竞争：你和'计算机'。
1.比赛将是一场T-1比赛，即每场比赛一场或每场6球。
2.两队将有3名球员每个。
3.将会进行折腾。您或计算机将首先播放。
4.对于每个球，将在0到7之间生成一个随机数。
•数字0 - 6表示运行。
•如果生成数字7则意味着玩家已经出局。
5.如果所有六个球都已经玩过，那么第一支球队的比赛将结束或者所有队员都出局了。
6.在第一局比赛结束时，将显示第一支球队的得分以及还剩下多少球员。
7.第二支球队将在之后比赛。对于每个球，将在0到7之间生成一个新的随机数。这些总数将代表第二支球队的得分。将显示球队比赛的得分。
8.最后在比赛结束时，将显示结果，即哪支球队获胜&哪支球队失利了。如果两支球队的得分和跑垒数相同，那将是一场平局。有相同数量的玩家可以玩。
我尝试过：
1. Create a game of cricket match. There will be two teams competing against each other: You & ‘The Computer’.
1. The game will be a T-1 match i.e., one over each or 6 balls each.
2. Both team will have 3 players each.
3. A toss will take place. Either you or the computer will play first.
4. Against each ball a random number will be generated between 0 to 7.
• Numbers 0 – 6 represent the runs made.
• If the number 7 is generated it means that the player is out.
5. The game for the first team will end if either all six balls have been played OR all team members are out.
6. At the end of the first innings, score of the first team will be displayed along with how many players were still left to play.
7. The second team will play afterwards. Against each ball a new random number will be generated between 0 to 7. The total of these would represent the score that the second team made. Score of the team playing will be displayed.
8. Finally at the end of the game, the results would be displayed i.e. which team won & which team lost. It will be a tie if both the teams scored the same number of runs & had equal number of players left to play.
What I have tried:
<pre>#include <iostream>
#include <string>
using namespace std;
struct match
{
int player=3;
int balls=6;
int score;
};
match computer;
match us;
int main()
{
int x;
x=rand()%2;
if (x==1)
{
cout<<"Computer will play ";
}
else
{
cout<<"Human will play ";
}
推荐答案
我们不做你的功课：这是有原因的。它就是为了让你思考你被告知的事情，并试着理解它。它也在那里，以便您的导师可以识别您身体虚弱的区域，并将更多的注意力集中在补救措施上。
亲自尝试，你可能会发现它不是和你想的一样困难！
如果遇到具体问题，请询问相关问题，我们会尽力提供帮助。但我们不打算为你做这一切！
We do not do your homework: it is set for a reason. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.
Try it yourself, you may find it is not as difficult as you think!
If you meet a specific problem, then please ask about that and we will do our best to help. But we aren't going to do it all for you!
一个有趣的链接，可以帮助你开始一个新项目：系统开发生命周期 - 维基百科 [ ^ ]
我们不做你的家庭作业。
HomeWork不会在乞求别人做你的技能时测试你的技能工作，它旨在让你思考并帮助你的老师检查你对你所学课程的理解，以及你应用它们时遇到的问题。
你的任何失败都会帮助你的老师发现你的弱点并设定补救措施。
所以，试一试，重读你的课程并开始工作。如果您遇到特定问题，请显示您的代码并解释这个问题，我们可能会提供帮助。
作为程序员，您的工作是创建算法解决特定问题，你不能依赖别人永远为你做，所以有一段时间你必须学会如何。而且越快越好。
当你要求解决方案时，就像试图通过培训其他人来学习开车一样。
创建算法基本上是找到数学并做出必要的调整以适应你的实际问题。
An interesting link to get you started on a new project: Systems development life cycle - Wikipedia[^]
We do not do your HomeWork.
HomeWork is not set to test your skills at begging other people to do your work, it is set to make you think and to help your teacher to check your understanding of the courses you have taken and also the problems you have at applying them.
Any failure of you will help your teacher spot your weaknesses and set remedial actions.
So, give it a try, reread your lessons and start working. If you are stuck on a specific problem, show your code and explain this exact problem, we might help.
As programmer, your job is to create algorithms that solve specific problems and you can't rely on someone else to eternally do it for you, so there is a time where you will have to learn how to. And the sooner, the better.
When you just ask for the solution, it is like trying to learn to drive a car by having someone else training.
Creating an algorithm is basically finding the maths and make necessary adaptation to fit your actual problem.
这篇关于如何使用C ++中的结构编写此问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
