如何在SQL存储过程中获取if else中的多个输出参数值? [英] How to get multiple output parameters values within if else in SQL stored procedure ?
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问题描述
I am writing stored procedure for login in which i want result through output parameters usertype and loginstatus values as 1 and 1 respectively.
Following is stored procedure code:
CREATE procedure [dbo].[usp_login]
(@userid nvarchar(50), @password nvarchar(50), @usertype int output, @loginstatus int output)
As
Begin
if exists(Select COUNT(User_Id) from User_Master where User_Id = @userid and Password = @password)
begin
select @usertype = User_Type from User_Master where User_Id = @userid and Password = @password;
set @loginstatus = 1;
end
else
begin
set @usertype = 0
set @loginstatus = 0;
end
End
I am executing the sp in ssms as follows:
declare @usrtype int;
declare @lgnstat int;
exec usp_login 'a', 'a', @usrtype output, @lgnstat output
print @usrtype
print @lgnstat
Now when i pass correct userid password i get result as 1,1 which is as expected.
But, when i pass wrong userid or password i get result as 1 which is expected as 0,0.
Please tell me where's the problem either in sp definition code or execution code ?
什么我试过了:
What I have tried:
CREATE procedure [dbo].[usp_login]
(@userid nvarchar(50), @password nvarchar(50), @usertype int output, @loginstatus int output)
As
Begin
if exists(Select COUNT(User_Id) from User_Master where User_Id = @userid and Password = @password)
begin
select @usertype = User_Type from User_Master where User_Id = @userid and Password = @password;
set @loginstatus = 1;
end
else
begin
set @usertype = 0
set @loginstatus = 0;
end
End
declare @usrtype int;
declare @lgnstat int;
exec usp_login 'z', 'z', @usrtype output, @lgnstat output -- passing wrong userid password
print @usrtype
print @lgnstat
推荐答案
这个存在在聚合上就像COUNT一样会返回true,因为它总是返回一些值,所以它永远不会访问else部分,
This "exists" on aggregate like COUNT will always returns true since it always returns some value, so it will never get to visit the "else" part,
if exists(Select COUNT(User_Id) from User_Master where User_Id = @userid and Password = @password)
请改为尝试:
if exists(Select 1 from User_Master where User_Id = @userid and Password = @password)
请更改以下代码: -
if((从User_Master中选择COUNT(User_Id),其中User_Id = @ userid和密码= @password)> 0)
从User_Master中选择@usertype = User_Type,其中User_Id = @ userid和密码= @password;
设置@loginstatus = 1;
结束
其他
开始
设置@usertype = 0
设置@loginstatus = 0;
结束
Please change the code like this:-
if ((Select COUNT(User_Id) from User_Master where User_Id = @userid and Password = @password)>0)
select @usertype = User_Type from User_Master where User_Id = @userid and Password = @password;
set @loginstatus = 1;
end
else
begin
set @usertype = 0
set @loginstatus = 0;
end
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