带有java的数字中所有奇数位的总和 [英] The sum of all the odd digits in a number with java
问题描述
我正在编写一个程序,用java计算数字中所有奇数位的总和。我得到格式转换错误的一些原因:
行:
System.out.printf(%s的奇数位之和:%f,数字,odd_digits_sum);
线程main0的奇数位的异常总和:java .util.IllegalFormatConversionException:f!= java.lang.Integer
at java.util.Formatter $ FormatSpecifier.failConversion(Unknown Source)
at java.util.Formatter $ FormatSpecifier.printFloat(Unknown Source)
at java.util.Formatter $ FormatSpecifier.print(Unknown Source)
at java.util.Formatter.format(Unknown Source)
at java.io.PrintStream.format(Unknown Source)
at java.io.PrintStream.printf(未知来源)
at practicebook.sum1.main(sum1.java:86)
import java.util.Scanner;
公共类sum1 {
public static void main(String [] args){
扫描仪输入=新扫描仪(系统。在);
System.out.print(Number:);
int number = input.nextInt();
input.close();
int odd_digits_sum = 0;
while(number> 0){
int digit = number%10;
if(digit%2!= 0){
odd_digits_sum + = digit;
}
number / = 10;
}
System.out.printf(%s的奇数位之和:%f,数字,odd_digits_sum);
//System.out.printf(\"number是+ number;
}
}
//结束主要}
//结束类
我的尝试:
- -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- --------------------------
FormatSpecifier.failConversion(未知来源)
at java.util.Formatter
FormatSpecifier.printFloat(Unknown Source)
at java.util.Formatter
FormatSpecifier .print(未知来源)
at java.util.Formatter.format(Unknown Source)
at java.io.PrintStream.format(Unknown Source)
at java.io.PrintStream.printf (未知来源)
at practicebook.sum1.main(sum1.java:86)
import java.util.Scanner;
公共类sum1 {
public static void main(String [] args){
扫描仪输入=新扫描仪(系统。在);
System.out.print(Number:);
int number = input.nextInt();
input.close();
int odd_digits_sum = 0;
while(number> 0){
int digit = number%10;
if(digit%2!= 0){
odd_digits_sum + = digit;
}
number / = 10;
}
System.out.printf(%s的奇数位之和:%f,数字,odd_digits_sum);
//System.out.printf(\"number是+ number;
}
}
//结束主要}
//结束类
我的尝试:
- -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- --------------------------
Im tyring to write a program that computes the sum of all the odd digits in a number with java. FOr some reason im getting a format conversion error:
at the line:
System.out.printf("Sum of %s's odd digits: %f", number, odd_digits_sum);
Sum of Exception in thread "main" 0's odd digits: java.util.IllegalFormatConversionException: f != java.lang.Integer at java.util.Formatter$FormatSpecifier.failConversion(Unknown Source) at java.util.Formatter$FormatSpecifier.printFloat(Unknown Source) at java.util.Formatter$FormatSpecifier.print(Unknown Source) at java.util.Formatter.format(Unknown Source) at java.io.PrintStream.format(Unknown Source) at java.io.PrintStream.printf(Unknown Source) at practicebook.sum1.main(sum1.java:86) import java.util.Scanner; public class sum1 { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Number: "); int number = input.nextInt(); input.close(); int odd_digits_sum = 0; while (number > 0) { int digit = number % 10; if (digit % 2 != 0) { odd_digits_sum += digit; } number /= 10; } System.out.printf("Sum of %s's odd digits: %f", number, odd_digits_sum); //System.out.printf("number is " + number); } } //end main} // end class
What I have tried:
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
FormatSpecifier.failConversion(Unknown Source) at java.util.Formatter
FormatSpecifier.printFloat(Unknown Source) at java.util.Formatter
FormatSpecifier.print(Unknown Source) at java.util.Formatter.format(Unknown Source) at java.io.PrintStream.format(Unknown Source) at java.io.PrintStream.printf(Unknown Source) at practicebook.sum1.main(sum1.java:86) import java.util.Scanner; public class sum1 { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Number: "); int number = input.nextInt(); input.close(); int odd_digits_sum = 0; while (number > 0) { int digit = number % 10; if (digit % 2 != 0) { odd_digits_sum += digit; } number /= 10; } System.out.printf("Sum of %s's odd digits: %f", number, odd_digits_sum); //System.out.printf("number is " + number); } } //end main} // end class
What I have tried:
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