字符串不能转换为JSONArray [英] String cannot be converted to JSONArray

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本文介绍了字符串不能转换为JSONArray的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想从一个php文件中获取数据。

I am trying to get data from a php file.

这是我的PHP code:

This is my PHP code:

$sql=mysql_query("select * from `tracking`");
while($row=mysql_fetch_assoc($sql))
$output[]=$row;
print(json_encode($output));

和我真正需要的所有数据。这是code我用它来获取和转换数据:

And I really need all the data. This is the code I use to get and convert the data:

String result = null;
InputStream is = null;
StringBuilder sb = null;

ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
try {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://server/getData.php");
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity entity = response.getEntity();
    is = entity.getContent();
} catch(Exception e) {
    Log.e("log_tag", "Error in http connection"+e.toString());
}

//convertion de la réponse en String
try {
    //BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"),8);
    BufferedReader reader = new BufferedReader(new InputStreamReader(is,"UTF-8"),8);
    sb = new StringBuilder();
    sb.append(reader.readLine() + "\n");

    String line="0";
    while ((line = reader.readLine()) != null) {
        sb.append(line + "\n");
        //sb.append(line);
    }

    is.close();
    result=sb.toString();             
} catch(Exception e) {
    Log.e("log_tag", "Error converting result "+e.toString());
}

// Affectation des données
try {
    JSONArray jArray = new JSONArray(result);
    Log.d("jArray", ""+jArray);
    JSONObject json_data= null;

    for(int i=0; i<jArray.length(); i++) {
        p = new Position();
        json_data = jArray.getJSONObject(i);

        Log.d("js", ""+json_data);
        id=json_data.getInt("id");
        lat=(float) json_data.getDouble("lat");
        lon=(float) json_data.getDouble("lon");
        speed=(float) json_data.getDouble("speed");
        alt=json_data.getDouble("alt");
        time=json_data.getString("time");
        date=json_data.getString("date");

        p.setId(id);
        p.setLat(lat);
        p.setLon(lon);
        p.setSpeed(speed);
        p.setAlt(alt);
        p.setDate(date);
        p.setTime(time);

        datasource.createPosition(p);
    }
} catch(JSONException e1) {
    Log.e("JSONEX", ""+e1);
} catch (ParseException e1) {
    e1.printStackTrace();
}

这真的适用于模拟器很好,但不是在我的Andr​​oid手机,我没有得到的原因。
现在,这是从服务器上我的JSON结果:

This really works on emulator nicely but not on my android phone and I don't get the reason.
Now this is my json result from the server:

[{"id":"180","lat":"33.894707","lon":"-6.327312","speed":"0.00000","alt":"397","date":"29/07/2012","time":"23:44"}]

[{"id":"180","lat":"33.894707","lon":"-6.327312","speed":"0.00000","alt":"397","date":"29/07/2012","time":"23:44"}]

这是一个有效的 JSONArray 验证在 http://jsonlint.com/

It's a valid JSONArray validated on http://jsonlint.com/

推荐答案

我发现了什么是错的JSON。 我发现在开始一个字符?加某处code,它是不可见的,直到我存储的logcat进入到一个文件中。所以我加了code线,现在工作得很好。

I found what was wrong with JSON. I found at the beginning a character "?" added somewhere in the code and it was not visible until I stored the logCat entry to a file. So I added the code line and it works fine now.

result = result.substring(1);

我希望这可以帮助别人,将来要感谢名单Waqas

I hope it may help someone in the future thanx to Waqas

这篇关于字符串不能转换为JSONArray的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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