如何将两个列表一起添加以创建一个最终列表 [英] How do I add two lists together to create one final list

问题描述

我有两个名单，一个名为免费小时，一个名为hoursbookedlist，我想将它们一起添加到名为总小时数的列表中



#Imports Time

随机导入

导入时间



freehours = []

nameslist = []

hoursbookedlist = []

totalhoursbooked = []

适用于范围内的学生（7）：

name =输入（输入学生姓名）

hoursbooked = int（输入（输入为学生预订的小时数））

while（hoursbooked< 10）：

打印（请重新输入预订的小时数：）

hoursbooked = int（输入（请为stundent1预订的小时数） ）

如果小时预订> 10和小时册< 15：

freehours.append（1）

elif int（hoursbooked> = 15）：

freehours.append（2）



nameslist.append（姓名）

hoursbookedlist.append（小时预订）



totalhoursbooked = freehours + hoursbookedlist





print（student \t hoursbooked \t freehours \t totalhoursbooked）

for i in range（7）：

print（nameslist [i]，\t，\ t，hoursbookedlist [i]，\ t ，\ t，freehours [i]，\t，\t，totalhoursbooked [i]）



我是什么尝试过：



我试过做totalhoursbooked = freehourslist + hoursbookedlist

解决方案

你已经在如何通过Python上的RANGE ERROR列出LIST INDEX [ ^ ]。请不要重新发布;如果您有要添加的信息，请编辑原始问题。

尝试并适应此示例：

 list1 = [1,2 ，3,4] 
 list2 = [5,6,7,8] 
 list3 = [和x的x（x）（list1，list2）] 

了解有关压缩Python版的更多信息[ ^ ]

有一个几种不同的方法。



最简单的方法是使用循环，如Richard的评论中所述。



你也可以使用 operator.add 和 map 命令：

< pre lang =python> import 运算符
totalhoursbooked = list（map（operator.add，freehourslist，hoursbookedlist））

参见地图的文档[ ^ ]：

Quote：

返回一个迭代器，它将函数应用于每个iterable项，产生结果。

然后列表函数将此迭代器转换为列表。



您还可以使用列表理解 [ ^ ]和 zip功能 [ ^ ]。

 totalhoursbooked = [a + b  for  a，b  in  zip（freehourslist，hoursbookedlist）] 

Z. ip创建一个迭代器，它聚合来自作为参数传递的每个迭代的元素。 （如果您将 zip 返回值转换为列表，您将看到一个元组列表，其中每个元组包含来自freehourslist的元素以及相应的hoursbookedlist元素）。

I have two lists one called free hours and one called hoursbookedlist and I want to add them together to a list called total hours booked

#Imports Time
import random
import time

freehours = []
nameslist = []
hoursbookedlist = []
totalhoursbooked = []
for student in range(7):
name = input("Enter students name ")
hoursbooked = int(input("Enter number of hours booked for the students "))
while (hoursbooked <10):
print("Please re-enter number of hours booked: ")
hoursbooked = int(input("please the number of hours that have been booked for stundent1 "))
if hoursbooked > 10 and hoursbooked < 15:
freehours.append(1)
elif int(hoursbooked >=15):
freehours.append(2)

nameslist.append(name)
hoursbookedlist.append(hoursbooked)

totalhoursbooked = freehours + hoursbookedlist


print ("student \t hoursbooked \t freehours \t totalhoursbooked")
for i in range(7):
print(nameslist[i],"\t","\t",hoursbookedlist[i],"\t","\t",freehours[i],"\t","\t", totalhoursbooked[i])

What I have tried:

I tried just doing totalhoursbooked = freehourslist + hoursbookedlist

解决方案

You already have an answer to this question at How do I get past LIST INDEX OUR of RANGE ERROR on Python[^]. Please do not repost; if you have information to add then edit your original question.

Try and adapt from this example:

list1 = [1,2,3,4]
list2 = [5,6,7,8]
list3 = [sum(x) for x in zip(list1, list2)]

Learn more about zip in Python[^]

There are a few different ways to do that.

The simplest way is using a loop, as mentioned in Richard's comment.

You can also use operator.add and the map command:

import operator
totalhoursbooked = list(map(operator.add, freehourslist, hoursbookedlist))

See the documentation of map[^]:

Quote:

Return an iterator that applies function to every item of iterable, yielding the results.

Then the list function transforms this iterator into a list.

You can also use a combination of list comprehension[^] and the zip function[^].

totalhoursbooked = [a + b for a, b in zip(freehourslist, hoursbookedlist)]

Zip makes an iterator that aggregates elements from each of the iterables passed as arguments. (If you'd convert the zip return value to a list, you'd see a list of tuples where each tuple contains an element from freehourslist with the corresponding hoursbookedlist element).

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