在分而治之的方法C ++中乘以大数 [英] Multiplying large numbers in divide and conquer method C++

问题描述

嗨

i不会将分数和征服方法中的大数字乘以turbo c ++

i需要它

请帮帮我



我尝试过的事情：



i用长数到10位来解决它/>
i希望它为+10位数

其他朋友对我说它解决了数组

解决方案

我们不做你的作业：这是有原因的。它就是为了让你思考你被告知的事情，并试着理解它。它也在那里，以便您的导师可以识别您身体虚弱的区域，并将更多的注意力集中在补救措施上。



亲自尝试，你可能会发现它不是和你想的一样困难！



如果遇到具体问题，请询问相关问题，我们会尽力提供帮助。但我们不打算为你做这一切！

你要找的是一个bignum库（用于整数）或一个高精度的浮点库。 />


只需搜索这些条款。但是你可能找不到一个与旧的Turbo-C ++编译器开箱即用的方法。因此，您必须从源代码构建库并在必要时对Turbo-C ++编译器应用修改。



请不要重新发布问题;即使使用其他帐户。

Quote：

在分而治之的方法中乘以大数字

据我了解你的问题，没有分而治之的方法来乘以2个大数。细节可能有所不同，但基本上有一种方法。

Quote：

其他朋友们告诉我它用数组解决了

数组是存储非常大数量的切片的方法，但你必须设计存储，检索和进行乘法的方法。

存在可以处理这些数字的库，它被命名为BigInt。

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我们不做你的HomeWork。

HomeWork不会在乞求其他人做你的工作时测试你的技能，它会让你思考并帮助你的老师检查你对你所学课程的理解以及你所遇到的问题。应用它们。

你的任何失败都会帮助你的老师发现你的弱点并设定补救措施。

所以，试一试，重读你的课程并开始工作。如果您遇到特定问题，请显示您的代码并解释这个问题，我们可能会提供帮助。



作为程序员，您的工作是创建算法解决特定问题，你不能依赖别人永远为你做，所以有一段时间你必须学会​​如何。而且越快越好。

当你要求解决方案时，就像试图通过培训其他人来学习开车一样。

创建算法基本上是找到数学并做出必要的调整以适应你的实际问题。

hi
i wont to multiplying large numbers in divide and conquer method with turbo c++
i need it
please help me

What I have tried:

i solve it with long number to 10 digit
i want it for +10 digit
Other friends say to me it solved with arrays

解决方案

We do not do your homework: it is set for a reason. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.

Try it yourself, you may find it is not as difficult as you think!

If you meet a specific problem, then please ask about that and we will do our best to help. But we aren't going to do it all for you!

What you are looking for is a "bignum" library (for integers) or a high-precision floating point library.

Just search for these terms. But you might not found one that works out-of-the-box with the old Turbo-C++ compiler. So you have to the build the library from the sources and apply modifications for the Turbo-C++ compiler if necessary.

Please don't repost questions; even when using another account.

Quote:

Multiplying large numbers in divide and conquer method

As far as I understand your question, there is no "divide and conquer method" to multiply 2 large numbers. Details may vary, but there is basically 1 method.

Quote:

Other friends say to me it solved with arrays

An array is the way to store slices of a very large number, but you have to devise the way to store, retrieve and do the multiplication.
Libraries exist that can handle such numbers, it is named BigInt.
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We do not do your HomeWork.
HomeWork is not set to test your skills at begging other people to do your work, it is set to make you think and to help your teacher to check your understanding of the courses you have taken and also the problems you have at applying them.
Any failure of you will help your teacher spot your weaknesses and set remedial actions.
So, give it a try, reread your lessons and start working. If you are stuck on a specific problem, show your code and explain this exact problem, we might help.

As programmer, your job is to create algorithms that solve specific problems and you can't rely on someone else to eternally do it for you, so there is a time where you will have to learn how to. And the sooner, the better.
When you just ask for the solution, it is like trying to learn to drive a car by having someone else training.
Creating an algorithm is basically finding the maths and make necessary adaptation to fit your actual problem.

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