如何在C中指向函数？ [英] How to do pointer to function in C?

问题描述

我想做指向返回指针的功能

喜欢这个功能

I want to do point to function that return me a pointer
Like this function

int *test(int x)
{
	int y=x*x;
	int *p=&x;
	return p;
	}

我的尝试：



我尝试了这个选项int main但我总是得到错误

What I have tried:

I tried this option int main but i get error all the time

int (**t)(int x);
		t=&test;

int (**t)(int x);
		t=*test;

int (**t)(int x);
    t=&(*test);

int (**t)(int x);
		t=*(&test);

推荐答案

试试这个

int *（* myfunc）（int x）;



myfunc = test;



打电话给

int * ret = myfunc（3）;



这对我来说已经有一段时间但是试一试。



注意：您将返回参数变量的地址。一旦你回到调用程序，它就消失了。大错误!!!

Try this
int* (*myfunc)(int x);

myfunc = test;

Call as
int* ret = myfunc(3);

It's been a while for me but give this a try.

Note: You're returning the address of an parameter variable. It's gone once you've returned to the calling routine. Big Error !!!

建议：花时间学习语言，这是一个学习C和C ++的神话讲座，包括答案。

这里是语言作者的C和C ++参考书的链接。注意，C是C ++的祖先，所以知道C对C ++总是有用。

C编程语言 - 维基百科，免费的百科全书 [ ^ ]

https://hassanolity.files.wordpress.com/2013/11/the_c_programming_language_2。 pdf [ ^ ]

http：//www.ime.usp。 br / ~pf / Kernighan-Ritchie / C-Programming-Ebook.pdf [ ^ ]



C ++编程语言 [ ^ ]

Advice: Take time to learn properly the language, here is a very god lecture to learn C and C++, answer included.
Here is links to references books on C and C++ by the authors of the languages. Note than C is the ancestor of C++, so knowing C is always useful with C++.
The C Programming Language - Wikipedia, the free encyclopedia[^]
https://hassanolity.files.wordpress.com/2013/11/the_c_programming_language_2.pdf[^]
http://www.ime.usp.br/~pf/Kernighan-Ritchie/C-Programming-Ebook.pdf[^]

C++ Programing Language[^]

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