onFling（）2D动画发行 [英] onFling() 2D Animation Issue
问题描述
我想运行一个非常简单的2D动画，当我扔的图像视图。我也参与了这一活动2。
I'm trying to run a very simple 2D animation when I fling an image view. I have 2 activities involved in this.
本的GameCanvas
The GameCanvas
@Override
public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX,
float velocityY)
{
if(GameWindow.getContext() == null)
return false;
if((e1.getY() >= GameWindow.getHeight()) && (e1.getY() <= GameWindow.getBottom()))
{
try
{
if (Math.abs(e1.getY() - e2.getY()) > SWIPE_MAX_OFF_PATH)
return false;
// right to left slap
if((e1.getX() - e2.getX() > SWIPE_MIN_DISTANCE) && (Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY))
{
slappingLeft = true;
//Animate Slap
GameWindow.update();
if(!running)
running = true;
}
else if ((e2.getX() - e1.getX() > SWIPE_MIN_DISTANCE) && (Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY))
{
slappingRight = true;
//Animate Slap
GameWindow.update();
if(!running )
running = true;
}
}
catch (Exception e)
{
//nothing
}
}
slappingLeft = slappingRight = running = false;
return true;
}
而GameWindow
And the GameWindow
private RefreshHandler mRedrawHandler = new RefreshHandler();
class RefreshHandler extends Handler
{
@Override
public void handleMessage(Message msg) {
GameWindow.this.update();
GameWindow.this.invalidate();
}
public void sleep(long delayMillis) {
this.removeMessages(0);
sendMessageDelayed(obtainMessage(0), delayMillis);
}
};
public void update()
{
//animate slap
if(GameCanvas.slappingLeft)
{
for(int i = 0; i < 500; i+=100)
{
GameCanvas.SlapLeft();
mRedrawHandler.sleep(100);
}
GameCanvas.SetImage();
//this.invalidate();
}
else if(GameCanvas.slappingRight)
{
for(int i = 0; i < 500; i+=100)
{
GameCanvas.SlapImage();
mRedrawHandler.sleep(100);
}
GameCanvas.SetImage();
//this.invalidate();
}
}
我将不胜AP preciate如果有人可以帮助我弄清楚这个问题了。我已经尝试了许多不同的方法这个问题。
I would greatly appreciate if anyone helps me figure this problem out. I have tried many different approaches to this problem.
我只是想显示SlapImage半秒，然后恢复到正常的图像，直到onFling再次调用。
I just want to show the SlapImage for half a second, then revert back to the normal image till onFling is called again.
如果你想看到SetImage（），SlapLeft（），和SetImage（），让我知道！
If you would like to see SetImage(), SlapLeft(), and SetImage(), let me know!
非常感谢事先！
修改的
EDIT
的GameCanvas不是画布OBJ。它的一个活动，setsContentView（R.layout.game_canvas）
GameCanvas is not a Canvas obj. Its an activity that setsContentView(R.layout.game_canvas)
GameWindow是一个自定义的ImageView
GameWindow is a custom ImageView
推荐答案
经过一番考虑，我决定实施此解决方案。我认为它的工作原理相当不错。
After some consideration, i decided to implement this solution. I think it works fairly well.
我仍然不知道为什么我的previous办法没有奏效。如果有人仍想阐述我会AP preciate。
I'm still not sure why my previous way didn't work. If anyone would still like to elaborate I would appreciate.
在GameCanvas。我创造了这个主题。
GameCanvas. I created this thread.
resetSlap = new Thread()
{
public void run()
{
while(true)
{
try
{
Thread.sleep(500);
GameWindow.post(new Runnable()
{
public void run()
{
GameWindow.setImageBitmap(images[0]);
GameWindow.postInvalidate();
}
});
} catch (InterruptedException e)
{
e.printStackTrace();
}
}
}
};
Baiscally，每半秒我想图像复位到正常
Baiscally, every half-second I want to reset the image back to normal
然后，在我写的OnFling
Then in the OnFling I wrote
@Override
public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX,
float velocityY)
{
if(GameWindow.getContext() == null)
return false;
if((e1.getY() >= GameWindow.getHeight()) && (e1.getY() <= GameWindow.getBottom()))
{
try
{
if (Math.abs(e1.getY() - e2.getY()) > SWIPE_MAX_OFF_PATH)
return false;
// right to left slap
if((e1.getX() - e2.getX() > SWIPE_MIN_DISTANCE) &&
(Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY))
{
slappingLeft = true;
//Animate Slap
SlapLeft();
SlapSound();
if(voice.nextInt(10) < 3)
{
Voice.start();
}
}
// left to right slap
else if ((e2.getX() - e1.getX() > SWIPE_MIN_DISTANCE) &&
(Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY))
{
slappingRight = true;
//Animate Slap
SlapImage();
SlapSound();
if(voice.nextInt(10) < 3)
{
Voice.start();
}
}
}
catch (Exception e)
{
//nothing
}
}
slappingLeft = slappingRight = false;
return true;
}
基本上，如果我被拍走了，我会叫拍击离开，等待重置线程，如果我是正确的拍打我会打电话巴掌右和等待线程重新设置。
Basically, if I was slapping left I would call Slap left and wait for the thread to reset and if i was slapping right I would call Slap Right and wait for the thread to reset.
这个答案很适合我的情况。我希望这有助于：D
This answer works well for my situation.. I hope this helps :D
感谢大家的帮助。
这篇关于onFling（）2D动画发行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
