C＃ - 我如何分配这个变量？ [英] C# - how would I assign this variable?

问题描述

我的代码是：

  public   class  PublicPrivate：MonoBehaviour {
 
  public   float  level = 10f; 
  float  health = level * 10f; 
 
  void 更新（）{
  if （health <  =  0 ）{
 Debug.Log（  你已经死了。）; 
} 
} 

然而，当我调试时，它告诉我：

  public   float  level = 10f; 
  float  health = level * 10f; 
字段初始化程序无法引用非静态字段，方法或属性'  PublicPrivate.level' 

我理解为什么，但是我无法弄清楚我应该将我的'health'变量更改为，因为float或int不行。有任何想法吗？目前正在学习C＃所以如果这个问题有明显的答案，请原谅我。



我尝试了什么：



我试过将它改成int和double，都没有用。不太确定还有什么可以尝试。

解决方案

其他两个解决方案都是正确的，你不能使用一个字段来初始化另一个。但是，对于这种情况，有一个非常简单的解决方案，为默认级别值定义一个常量，并根据它初始化两者：

  public   class  PublicPrivate：MonoBehaviour {
  const   float  defaultLevel = 10f; 
  public   float  level = defaultLevel; 
  float  health = defaultLevel * 10f; 

你甚至可以做得更好，摆脱尽可能多的内联常量支持明确命名的常量，并且具有：

  public   class  PublicPrivate：MonoBehaviour {
  const   float  defaultLevel = 10f; 
  public   float  level = defaultLevel; 
  const   float  levelToHealthFactor = 10f; 
  float  health = defaultLevel * levelToHealthFactor; 

问题不在于变量的类型。您不能在由另一个字段变量初始化的类中具有字段变量。这意味着您不能使用级别来初始化 health 。

这是因为：



您不能使用实例变量来初始化另一个实例变量。为什么？因为编译器可以重新排列这些 - 不能保证在defaultReminder之前初始化提醒，所以上面的行可能会抛出NullReferenceException。





您可以在此链接阅读更多相关信息



其中一个解决方案是在构造函数中移动第二个变量初始化，或者两个变量初始化如：



< pre lang =c＃> public class PublicPrivate：MonoBehaviour {

< span class =code-keyword> public float 级别;
float health;

public PublicPrivate（）
{
level = 10f;
health = level * 10f;
}

void 更新（）{
if （health < = 0 ）{
Debug.Log（ 你已经死了。）;
}
}

你也可以参考这个问题

My code is:

public class PublicPrivate : MonoBehaviour {

	public float level = 10f;      
	float health = level * 10f;  

	void Update () {
		if (health <= 0) {
			Debug.Log ("You have died.");
		}
	}

However, when I debug, it tells me:

    public float level = 10f; 
	float health = level * 10f;
A field initialiser cannot reference the non-static field, method, or property 'PublicPrivate.level' 

I understand why, but I can't figure out what I should change my 'health' variable to since a float or int won't work. Any ideas? Currently learning C# so please forgive me if this question has an obvious answer.

What I have tried:

I've tried changing it to an int and a double, neither worked. Not too sure what else to try.

解决方案

The other two Solutions are correct, you cannot use one field to initialize another. For this case, however, there is very a simple solution, define a constant for the default level value and initialize both based on that:

public class PublicPrivate : MonoBehaviour {
  const float defaultLevel = 10f;
  public float level = defaultLevel;
  float health = defaultLevel * 10f;

You could even do better, by getting rid of as many in-line constants as possible in favor of a clearly named constant, and have:

public class PublicPrivate : MonoBehaviour {
  const float defaultLevel = 10f;
  public float level = defaultLevel;
  const float levelToHealthFactor = 10f;
  float health = defaultLevel * levelToHealthFactor;  

The problem is not the type of variable. You cannot have a field variable in a class being initialised by another field variable. It means that you are not allowed to use level for the initialisation of health.

This is because :

You cannot use an instance variable to initialize another instance variable. Why? Because the compiler can rearrange these - there is no guarantee that reminder will be initialized before defaultReminder, so the above line might throw a NullReferenceException.


You can read more details about it at this link

one of the solution is to move the second variable initialization in the constructor, or both variables initialization like:

public class PublicPrivate : MonoBehaviour {
 
	public float level;      
	float health;

        public PublicPrivate()
        {
           level = 10f;
           health = level * 10f;
        }  
 
	void Update () {
		if (health <= 0) {
			Debug.Log ("You have died.");
		}
	}

you can also refer to this question

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