如何使用mysql中的jquery一次绑定两个下拉列表 [英] How to bind two dropdownlists at a time using jquery from mysql
问题描述
我有两个下拉列表如何使用后端的jquery绑定它
我尝试了什么:
$ .ajax({
类型:POST,
contentType:application / json; charset = UTF-8,
url:ddlBind.aspx / ddlDataBind,
data:{},
dataType:json,
成功:函数(数据){
var SharedAOC = JSON.parse(data.d);
var finalData = SharedAOC.Table;
调试器;
$ .each(finalData,function(key,value){
$(#ddlCity)。append($(< option>< / option>)。val(value.City).html(value.City));
$( #ddlState)。append($(< option>< / option>)。val(value.State).html(value.State));
});
调试器;
$。 each(finalData,function(key,value){
$(#ddlState)。append($(< option>< / option>)。val(value.State) .html(value.State));
});
},
.ajax({
类型:POST,
contentType:application / json; charset = UTF-8,
url:ddlBind.aspx / ddlDataBind,
data:{},
dataType:json ,
成功:函数(数据){
var SharedAOC = JSON.parse(data.d);
var finalData = SharedAOC。表;
调试器;
.each(finalData,function(key,value){
>
( #ddlCity)。附加(
I have two dropdown lists how to bind that using jquery from back end
What I have tried:
$.ajax({
type: "POST",
contentType: "application/json; charset=UTF-8",
url: "ddlBind.aspx/ddlDataBind",
data: {},
dataType: "json",
success: function (data) {
var SharedAOC = JSON.parse(data.d);
var finalData = SharedAOC.Table;
debugger;
$.each(finalData, function (key, value) {
$("#ddlCity").append($("<option></option>").val(value.City).html(value.City));
$("#ddlState").append($("<option></option>").val(value.State).html(value.State));
});
debugger;
$.each(finalData, function (key, value) {
$("#ddlState").append($("<option></option>").val(value.State).html(value.State));
});
},
.ajax({
type: "POST",
contentType: "application/json; charset=UTF-8",
url: "ddlBind.aspx/ddlDataBind",
data: {},
dataType: "json",
success: function (data) {
var SharedAOC = JSON.parse(data.d);
var finalData = SharedAOC.Table;
debugger;
.each(finalData, function (key, value) {
("#ddlCity").append(
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