复杂的属性类型 [英] Complex property types

问题描述

我有一个名为TerminalConnectionParameters的类，它包含一些不同类型的字段，如Hostname，IPAddress，UserName，Password等。



我想用这个类键入Dummy类的属性，例如：

  public   class  Dummy 
 {
  private  TerminalConnectionParameters _parameters; 
  public  TerminalConnectionParameters参数
 {
  get  
 { 
  //  在这里做一些花哨的计算 
 返回 _parameters; 
} 
  set  
 {
 _parameters =  value  ; 
  //  在这里做一些花哨的计算 
} 
} 
} 

这确保我可以获取或设置Dummy对象的整个Parameters类。

到目前为止一切都那么好，但是，如果我想使用这个属性如下：

 objectDummy.Parameters.Hostname = < span class =code-string>  dummyRouter; 

当然，这个赋值语句不会设置dummyObject的内部_parameters字段的值。那么呢？什么是实现这样的属性编写器的正确方法，而不必独特地创建TerminalConnectionParameters的每个字段的属性访问器？

我知道如下的简单方法，但没有更好的解决方案？

 TerminalConnectionParameters temp = objectDummy.Parameters; 
 temp.HostName =   dummyRouter; 
 objectDummy.Parameters = temp; 

这个问题背后的原因是我想用PropertyGrid来处理表格的内部_parameters对象。



我尝试过：



如上例所示。

解决方案

实际上，如果您的_parameters成员已经初始化，那么您的第一个赋值语句很好 - 您可以在声明中执行此操作

 私人 TerminalConnectionParameters _parameters  =  new  TerminalConnectionParameters（）; 

或在getter中

  private  TerminalConnectionParameters _parameters  =  null  ; 
  public  TerminalConnectionParameters参数
 {
  get  
 { 
  如果（_parameters  -   null ）
 _parameters =  new  TerminalConnectionParameters（）;  
  //  在这里做一些花哨的计算 
 返回 _parameters; 

现在，一旦你是确保初始化，您需要做的就是用以下属性装饰参数属性，设计师将神奇地处理其余的事情：

 [DesignerSerializationVisibility（DesignerSerializationVisibility.Content）] 
  public  TerminalConnectionParameters参数
 {
 

您可以序列化虚拟对象中的参数，并在宿主对象中反序列化。

谢谢Midi_Mick，就是这样。不知怎的，我觉得它必须简单......： - ）

I have a class named TerminalConnectionParameters which contains a few differently typed fields, like Hostname, IPAddress, UserName, Password, etc.

I want to used this class type as a property of a Dummy class, like :

public class Dummy
{
    private TerminalConnectionParameters _parameters;
    public TerminalConnectionParameters Parameters
    {
      get
      {
        // do some fancy calculation here
        return _parameters;
      }
      set
      {
        _parameters = value;
        // do some fancy calculation here
      }
    }
}

This ensures that I can get or set the whole Parameters class of a Dummy object.
So far so good, but what, if I want to use this property like :

objectDummy.Parameters.Hostname= "dummyRouter";

For sure, this assignment statement will not set the value of the dummyObject's internal _parameters field. But what then ? And what is the correct way to implenment such property writer without having to create a property accessor of each field of the TerminalConnectionParameters uniquely ?
I am aware of the trivial way as below, but is there no better solution ?

TerminalConnectionParameters  temp = objectDummy.Parameters;
temp.HostName = "dummyRouter";
objectDummy.Parameters = temp;

And the reason behind this question is that I want to use PropertyGrid to deal with the internal _parameters object of a Form.

What I have tried:

As outlined in the example above.

解决方案

Actually, your first assignment statement is good providing your _parameters member has been initialised - you can either do that in the declaration

private TerminalConnectionParameters _parameters = new TerminalConnectionParameters();

or in the getter

private TerminalConnectionParameters _parameters = null;
    public TerminalConnectionParameters Parameters
    {
      get
      {
        if (_parameters - null)
            _parameters = new TerminalConnectionParameters();
        // do some fancy calculation here
        return _parameters;

Now, once you are ensured of initialisation, all you need to do is decorate the Parameters property with the following attribute, and the designer will magically take care of the rest:

[DesignerSerializationVisibility(DesignerSerializationVisibility.Content)]
public TerminalConnectionParameters Parameters
{

You could serialize the parameters in the dummy object, and deserialize it in the host object.

Thank you Midi_Mick, that was it. Somehow I felt it must be simple...:-)

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