嵌套if else问题 [英] Nested if else question

问题描述

样品输出



输入房间类型：1

输入月份：Dec

输入没有天数：3

输入房间类型：2

输入月份：Jan

输入日期：4

输入房间类型：0

要支付的总金额：.......



那里只有3种类型的房间。 1,2和3.如果用户输入任何其他如果应出现无效的房间类型。问题是可以通过为房间类型输入0来退出，如示例输出中所示。但在我的情况下，它表示无效的房间类型和后显示总金额。你可以帮我吗。



我尝试过：



#include

sample output

enter type of the room: 1
enter the month: Dec
enter no of days: 3
enter type of the room: 2
enter the month: Jan
enter no of days: 4
enter type of the room: 0
total amount to be paid: .......

There are only 3 type of rooms. 1, 2 and 3. if user enters any other if should appear "Invalid room type". The question says can exit by entering 0 for the room type as shown in the sample output. but in my case it says invalid room type and after shows total amount. can you please help me.

What I have tried:

#include

推荐答案

while(true)
   {
   // Get your value
   ...
   switch(enteredRoomType)
      {
      case 0:
         // All done - exit the app.
         exit(0);
      case 1:
      case 2:
      case 3:
         // All ok.
         break;
      default:
         cout << "Invalid room type";
         continue;
      }
   ...
   }

不应该嵌套 如果。那应该是如果 chain （一系列 if-else if 语句）或者，更好的切换构造。

That shouldn't be nested if. That should be if chain (a sequence of if-else if statements) or, better a switch construct.

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