如何在oop（inheritane）中使用朋友资金？ [英] How can use the friend fundtion in oop(inheritane)?

问题描述

我想访问与另一个类继承的不同类的数据，但我不知道我怎么做我尝试过如下..所以帮助我？

这里是样本我的代码..

A类{};

类B {};

类C {};

级D：公共A，公共B，公共C {

//这里我想打电话给朋友基金这么帮帮我？

};



我尝试过：



朋友无效结果（伊斯兰，Pakstudy，电脑）; / /它是伊斯兰等不同类别的decler

无效结果（伊斯兰是，Pakstudy pk，计算机cm）{

system（cls）;

cout<<\ t \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ < endl;

cout<<\t\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\标记\t获得标记<< endl;

cout<<\ t圆形：1 \t \t 25 \t<< is.ismarks<< endl;



结果（Islammic; Pakstudy; Computer）; //这里是错误，这是我想要访问数据的另一个类但是syntex错误

解决方案

你调用带参数的函数（在你的情况下是伊斯兰教，Pakstudy，电脑）。

参数用逗号（，）分隔：



结果（伊斯兰，Pakstudy，电脑）;



这是否会解决你的朋友问题，我不知道没看到整个代码。



Matt

i want to access the data of different classes which are inherit with another class but i dont know how i can do i have tried as below.. so help me?
here is the sample of my code..
class A{};
class B{};
class C{};
class D:public A,public B,public C{
// here i want to call friend fundition so help me?
};

What I have tried:

friend void result(Islamic,Pakstudy,Computer);// it is decler in different classes like Islamic etc.
void result(Islamic is,Pakstudy pk,Computer cm){
system("cls");
cout<<"\t\t\t\t\t\t\t RESULT OF QUIZ COMMPETATION\t\t\n\n"<<endl;
cout<<"\t\t\t\t\t\t\t Quastion Category: Islamic Study \t\t Total marks \t Obtain Marks "<<endl;
cout<<"\t\t\t\t\t\t\t Round : 1 \t\t 25 \t "<<is.ismarks<<endl;

result(Islammic;Pakstudy;Computer); //here is error ,this an other class in i want to access data but syntex error

解决方案

You call a function with arguments (in your case Islamic, Pakstudy, Computer).
Arguments are separated by commas (,):

result(Islammic,Pakstudy,Computer);

Whether that will fix your friend problem, I don't know without seeing the entire code.

Matt

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