这个java正则表达式有什么不对 [英] Whats wrong in this java regex
问题描述
任何人都可以告诉我在java的正则表达式中有什么错误，matcher.find与它不匹配。我要匹配的字符串是----- DATEADD（'2016-09-18T00：00：00'，'year'，'1'）
正在使用的正则表达式是
1）^ [DATEADD] \\（[\\'] [\\w - ：] + [ \\ '] [\\，] [\\'] [A-ZA-Z _] [\\ '] [\\，] [\\'] [\\ \\\d] + [[\\']] [\\]] $
2）^ [DATEADD] [\\（] [\\\\ ] * [] [A-ZA-Z0-9 _。] + [...] [A-ZA-Z _] [...] [\\d] + [[\\']] [\\\\] * [\\]] $
我尝试了什么：
我尝试了很多正则表达式，但没有一个匹配
Can anybody please tell me whats wrong in the regex for java the matcher.find is not matching it. My string to match is this ----- DATEADD('2016-09-18T00:00:00','year','1' )
The regex I am using is
1)^[DATEADD]\\([\\'][\\w-:]+[\\'][\\,][\\'][a-zA-Z_][\\'][\\,][\\'][\\d]+[[\\']][\\)]$
2)^[DATEADD][\\(][\\s]*[.][a-zA-Z0-9_.]+[...][a-zA-Z_][...][\\d]+[[\\']][\\s]*[\\)]$"
What I have tried:
I have tried a lot of regex but none of them are matching
推荐答案
2 ）^ [DATEADD] [\\（] [\\s] * [] [A-ZA-Z0-9 _。] + [...] [A-ZA-Z _] [... ] [\\d] + [[\\']] [\\\\] * [\\]]
2)^[DATEADD][\\(][\\s]*[.][a-zA-Z0-9_.]+[...][a-zA-Z_][...][\\d]+[[\\']][\\s]*[\\)]
我尝试了什么：
我已经尝试了很多正则表达式，但没有一个匹配
"
What I have tried:
I have tried a lot of regex but none of them are matching
好......首先要注意的是'''和']'分隔可以在一个位置的字符集合。例如，[0123456789]或[0-9]将匹配单个数字。
因此[DATEADD]将匹配单个字符'A'，'D '，'E'或'T' - 而不是一系列字符。
要匹配序列DATEADD，只需键入不带方括号的字符。
请看这里： Pattern（Java Platform SE 7） [ ^ ] - 它可能会有所帮助。
并获得 Expresso 的副本[ ^ ] - 它是免费的，它会检查并生成正则表达式。
OK...the first thing to note is that '[' and ']' delimit a collection of characters that can be in a single location. For example "[0123456789]" or "[0-9]" will each match a single digit.
So "[DATEADD]" will match a single character that is an 'A', 'D', 'E', or 'T' - and not a sequence of characters.
To match the sequence "DATEADD" just type the characters without the square brackets.
Have a look here: Pattern (Java Platform SE 7 )[^] - it may help.
And get a copy of Expresso[^] - it's free, and it examines and generates Regular expressions.
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